自动倒数计时器 - Javascript
Auto Countdown Timer - Javascript
我正在尝试让我的计时器 在第一个倒计时结束后 new Date()
自动更改为第二个 new Date()
。
这样做的目的是为了万一我需要更改倒计时的日期,我将不必在 js 文件过期后手动编辑和上传它。但是我还没搞清楚怎么办。
下面是我试过的脚本,输出是 "EXPIRED"。我哪里做错了?感谢您的支持!
<script>
// Set the date we're counting down to
var countDownDate = new Date("Jan 5, 2020 14:00:00").getTime();
var countDownDate2 = new Date("Jan 15, 2020 14:00:00").getTime();
// Update the count down every 1 second
var x = setInterval(function() {
// Get today's date and time
var now = new Date().getTime();
// Find the distance between now and the count down date
var distance = countDownDate - now;
var distance2 = countDownDate2 - now;
var a = distance;
// Time calculations for days, hours, minutes and seconds
var days = Math.floor(a / (1000 * 60 * 60 * 24));
var hours = Math.floor((a % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
var minutes = Math.floor((a % (1000 * 60 * 60)) / (1000 * 60));
var seconds = Math.floor((a % (1000 * 60)) / 1000);
// Output the result in an element with id="demo"
document.getElementById("demo").innerHTML = days + "d " + hours + "h "
+ minutes + "m " + seconds + "s ";
// Change to another exp.
if (distance < 0 && distance2 >0) {
function changeDate() {
a = distance2;
}
}
// If the count down is over, write some text
else {
clearInterval(x);
document.getElementById("demo").innerHTML = "EXPIRED";
}
}, 1000);
</script>
第一个问题是看distance是否小于1,distance2是否大于1。但是当 distance 仍然有效时(在撰写本文时就是这种情况),它会自动进入 else 分支。
因此,要解决此问题,您需要:
// If the count down is over, write some text
if (distance2 < 0) {
clearInterval(x);
document.getElementById("demo").innerHTML = "EXPIRED";
}
编辑:
第二个问题是您在打印后更改变量。因此,您必须转到 a 的定义并将其更改为:
var a = distance;
收件人:
var a;
if (distance < 0 && distance2 >0) {
a = distance2;
} else {
a = distance;
}
我正在尝试让我的计时器 在第一个倒计时结束后 new Date()
自动更改为第二个 new Date()
。
这样做的目的是为了万一我需要更改倒计时的日期,我将不必在 js 文件过期后手动编辑和上传它。但是我还没搞清楚怎么办。
下面是我试过的脚本,输出是 "EXPIRED"。我哪里做错了?感谢您的支持!
<script>
// Set the date we're counting down to
var countDownDate = new Date("Jan 5, 2020 14:00:00").getTime();
var countDownDate2 = new Date("Jan 15, 2020 14:00:00").getTime();
// Update the count down every 1 second
var x = setInterval(function() {
// Get today's date and time
var now = new Date().getTime();
// Find the distance between now and the count down date
var distance = countDownDate - now;
var distance2 = countDownDate2 - now;
var a = distance;
// Time calculations for days, hours, minutes and seconds
var days = Math.floor(a / (1000 * 60 * 60 * 24));
var hours = Math.floor((a % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
var minutes = Math.floor((a % (1000 * 60 * 60)) / (1000 * 60));
var seconds = Math.floor((a % (1000 * 60)) / 1000);
// Output the result in an element with id="demo"
document.getElementById("demo").innerHTML = days + "d " + hours + "h "
+ minutes + "m " + seconds + "s ";
// Change to another exp.
if (distance < 0 && distance2 >0) {
function changeDate() {
a = distance2;
}
}
// If the count down is over, write some text
else {
clearInterval(x);
document.getElementById("demo").innerHTML = "EXPIRED";
}
}, 1000);
</script>
第一个问题是看distance是否小于1,distance2是否大于1。但是当 distance 仍然有效时(在撰写本文时就是这种情况),它会自动进入 else 分支。
因此,要解决此问题,您需要:
// If the count down is over, write some text
if (distance2 < 0) {
clearInterval(x);
document.getElementById("demo").innerHTML = "EXPIRED";
}
编辑:
第二个问题是您在打印后更改变量。因此,您必须转到 a 的定义并将其更改为:
var a = distance;
收件人:
var a;
if (distance < 0 && distance2 >0) {
a = distance2;
} else {
a = distance;
}