SQL 行集的删除语句

Question

我需要通过使用 SQL（仅限 status =Loaded）比较 Table 2 来删除行集 Table 1（4 行集），否则保留行集为此 IG。

例如，来自TABLE 1 的IG 10 数据将被删除，而IG 60 数据将保持与未加载该IG 对应的所有状态。

Answer 1

您可以尝试以下解决方案。内部 SELECT 获取所有未成功加载的 IG 值。 DELETE 本身会删除 IG 值不在此列表中的所有行（加载不成功）IG 值。

DELETE FROM Table1 WHERE NOT IG IN (
  SELECT IG FROM Table2 WHERE Status <> 'Loaded'
)

为确保删除正确的行，您可以先使用以下 SELECT：

SELECT * FROM Table1 WHERE NOT IG IN (
  SELECT IG FROM Table2 WHERE Status <> 'Loaded'
)

demo on dbfiddle.uk

Answer 2

试试这个

delete From [TABLE 1]
where IG in
(
Select IG from [TABLE 2] a where not exists(Select 1 From [TABLE 2] b where a.IG  = b.IG and Status not in ('Loaded') )
)

Answer 3

您可以尝试以下查询

DELETE FROM TABLE1 WHERE IG NOT IN (SELECT IG FROM TABLE2 WHERE STATUS = 'ERROR')

Answer 4

使用 NOT IN 子句：

delete from TB1 where not IG in  (
  select IG from TB2 where status <> 'Loaded'
)

SQL 行集的删除语句

SQL delete statement for a rowset

sql

tsql

sql-server

sql-delete