在打字稿中扩展快速请求类型

Question

重复：

import { Router } from 'express';
import * as uuid from 'uuid';

我正在使用打字稿 3.6.4。我正在扩展 express.Request 类型，因为我想添加 id 字段：

interface request extends Express.Request {
    id: string
}

如果我使用设置 id 的中间件创建 post 方法：

router.post('/orders', (req: request, _res: express.Response, next) => {req.id = uuid.v1(); next();}, async function (req: request, res: express.Response) {
...
});

但是我在请求中遇到错误：request

tscongif.json

{
  "compilerOptions": {
    "target": "es6",
    "module": "commonjs",
    "lib": [
      "es5",
      "es6",
      "dom", 
      "es2017", 
      "esnext.asynciterable"
   ],
    "strict": true,
    "alwaysStrict": true,
    "noImplicitAny": true,
    "strictNullChecks": true,                 
    "strictFunctionTypes": true,              
    "strictPropertyInitialization": false,
    "noImplicitThis": true,
    "noUnusedLocals": true,
    "noUnusedParameters": true,
    "noImplicitReturns": true,
    "noFallthroughCasesInSwitch": true,
    "baseUrl": "./src",
    "esModuleInterop": true,
    "moduleResolution": "node",
    "allowSyntheticDefaultImports": true,

    "experimentalDecorators": true,
    "emitDecoratorMetadata": true,
    "forceConsistentCasingInFileNames": true,
    "sourceMap": true,
    "outDir": "./dist",
    "removeComments": true
  },
  "exclude": ["node_modules"],
  "include": [
    "./src/**/*", "./src/**/*.tsx", "./src/**/*.ts"
  ]
}

Answer 1

我想你正在寻找 declaration merging

您可以合并界面。在 global.d.ts 中声明您的界面，ts 将合并它。

declare global {
  declare module 'express' {
    export interface Request {
      id: string;
    }
  }
}

而且您可以在应用中的任何地方使用它

const id = Express.request.id;
const anythingElseFromRequestInterface = Express.request.baseUrl;

Answer 2

这个对我有用！

declare module "express" {
  interface Request {
    id: string
  }
}

在打字稿中扩展快速请求类型

extends express request type in typescript

types

request

extend

express

typescript