如何显示 3 个字段匹配的记录
How to show records were 3 fields match
我正在尝试编写一个查询,当 3 个特定字段相同但未知时,将列出 table 中的列:
TABLE:
FIELD 1 | FIELD 2 | FIELD 3 | FIELD 4
---------|--------------|------------|---------------
1 | 01-01-15 | 21 | 150
1 | 01-01-15 | 24 | 12
1 | 02-01-15 | 21 | 681
1 | 01-01-15 | 21 | 299
期望的结果:
FIELD 1 | FIELD 2 | FIELD 3 | FIELD 4
-------------|--------------|-------------|------------
1 | 01-01-15 | 21 | 150
1 | 01-01-15 | 21 | 299
抱歉 - 还是个新手!提前致谢!
计算具有相同组合的行数并过滤计数 > 1:
select *
from tab
qualify
count(*)
over (partition by field1, field2, field3) > 1
我正在尝试编写一个查询,当 3 个特定字段相同但未知时,将列出 table 中的列:
TABLE:
FIELD 1 | FIELD 2 | FIELD 3 | FIELD 4
---------|--------------|------------|---------------
1 | 01-01-15 | 21 | 150
1 | 01-01-15 | 24 | 12
1 | 02-01-15 | 21 | 681
1 | 01-01-15 | 21 | 299
期望的结果:
FIELD 1 | FIELD 2 | FIELD 3 | FIELD 4
-------------|--------------|-------------|------------
1 | 01-01-15 | 21 | 150
1 | 01-01-15 | 21 | 299
抱歉 - 还是个新手!提前致谢!
计算具有相同组合的行数并过滤计数 > 1:
select *
from tab
qualify
count(*)
over (partition by field1, field2, field3) > 1