在额外聚合上使用 Sum 和 Make Total
Use Sum on extra aggregation and Make Total
我想创建一个索引视图。
我有这个查询:
SELECT srvmn.BBC_ID AS Inventory,
srvInv.ObjectID,
srv.State,
SUM( IIF(srvInv.Direction = srvInv.ReverseBroken, 1, 0)) AS Broken,
SUM(IIF(srvInv.Direction = 0, 1, -1)) AS Sum,
COUNT_BIG(*) AS CountLines
FROM table1 srvmn
JOIN table2 srv
ON srv.ServiceManID = srvmn.ID
JOIN table3 srvInv
ON srv.ID = srvInv.ServiceID
WHERE srv.State > 321
AND srv.State <> 123
GROUP BY srvInv.ObjectID,
srv.State,
srvInv.Direction,
srvInv.ReverseBroken,
srvmn.BBC_ID
ORDER BY srvInv.ObjectID
所以,Sum 无法正常工作,我也用这种方法修复它:
SELECT A.Inventory,
A.ObjectID,
A.State,
A.Broken,
SUM(A.Sum) AS Sum
FROM
(
SELECT srvmn.BBC_ID AS Inventory,
srvInv.ObjectID,
srv.State,
IIF(srvInv.Direction = srvInv.ReverseBroken, 1, 0) AS Broken,
SUM(IIF(srvInv.Direction = 0, 1, -1)) AS Sum,
COUNT_BIG(*) AS CountLines
FROM table1 srvmn
JOIN table2 srv
ON srv.ServiceManID = srvmn.ID
JOIN table3 srvInv
ON srv.ID = srvInv.ServiceID
WHERE srv.State > 321
AND srv.State <> 123
GROUP BY srvInv.ObjectID,
srv.State,
srvInv.Direction,
srvInv.ReverseBroken,
srvmn.BBC_ID
) AS A
GROUP BY A.Inventory,
A.ObjectID,
A.State,
A.Broken;
结果正常,但索引视图中不允许派生表。
我尝试在 Sum 中使用 "Over Partition",但结果不正确。
我该如何解决这个问题?
正确结果:
Inventory ObjectID State Broken Sum
------------------------------------------------
NULL 2 500 0 -1
NULL 3 320 1 1
NULL 3 500 0 2
NULL 3 600 0 1
NULL 18 600 0 -1
NULL 20 600 0 -1
1162 20 600 0 1
NULL 24 600 0 1
NULL 26 310 0 -3
NULL 26 320 0 -1
NULL 26 600 0 7
442 26 500 0 8
442 26 500 1 1
442 26 600 0 -5
1162 26 600 0 0
NULL 27 500 0 4
NULL 27 600 0 2
1162 27 600 0 1
1162 28 600 0 3
不正常结果:
Inventory ObjectID State Broken Sum CountLines
-------------------------------------------------------------
NULL 2 500 0 -1 1
NULL 3 500 0 2 2
NULL 3 600 0 1 1
NULL 18 600 0 -1 1
1162 20 600 0 3 3
1162 20 600 0 -2 2
NULL 20 600 0 1 1
NULL 20 600 0 -2 2
NULL 24 600 0 -1 1
NULL 24 600 0 2 2
442 26 600 0 -7 7
NULL 26 600 0 -18 18
1162 26 600 0 1 1
NULL 26 600 0 25 25
442 26 500 1 1 1
442 26 600 0 2 2
1162 26 600 0 -1 1
442 26 500 0 8 8
NULL 27 600 0 -3 3
1162 27 600 0 1 1
您不应在 "Group By"
中使用字段 "srvInv.Direction"
请试一试:
SELECT
srvmn.BBC_ID AS Inventory,
srvInv.ObjectID,
srv.State,
SUM(IIF(srvInv.Direction = srvInv.ReverseBroken, 1, 0)) AS Broken,
SUM(IIF(srvInv.Direction = 0, 1, -1)) AS Sum
FROM table1 srvmn
JOIN table2 srv ON srv.ServiceManID = srvmn.ID
JOIN table3 srvInv ON srv.ID = srvInv.ServiceID
WHERE srv.State > 321 AND srv.State <> 123
GROUP BY
srvInv.ObjectID,
srv.State,
srvInv.ReverseBroken,
srvmn.BBC_ID
我想创建一个索引视图。
我有这个查询:
SELECT srvmn.BBC_ID AS Inventory,
srvInv.ObjectID,
srv.State,
SUM( IIF(srvInv.Direction = srvInv.ReverseBroken, 1, 0)) AS Broken,
SUM(IIF(srvInv.Direction = 0, 1, -1)) AS Sum,
COUNT_BIG(*) AS CountLines
FROM table1 srvmn
JOIN table2 srv
ON srv.ServiceManID = srvmn.ID
JOIN table3 srvInv
ON srv.ID = srvInv.ServiceID
WHERE srv.State > 321
AND srv.State <> 123
GROUP BY srvInv.ObjectID,
srv.State,
srvInv.Direction,
srvInv.ReverseBroken,
srvmn.BBC_ID
ORDER BY srvInv.ObjectID
所以,Sum 无法正常工作,我也用这种方法修复它:
SELECT A.Inventory,
A.ObjectID,
A.State,
A.Broken,
SUM(A.Sum) AS Sum
FROM
(
SELECT srvmn.BBC_ID AS Inventory,
srvInv.ObjectID,
srv.State,
IIF(srvInv.Direction = srvInv.ReverseBroken, 1, 0) AS Broken,
SUM(IIF(srvInv.Direction = 0, 1, -1)) AS Sum,
COUNT_BIG(*) AS CountLines
FROM table1 srvmn
JOIN table2 srv
ON srv.ServiceManID = srvmn.ID
JOIN table3 srvInv
ON srv.ID = srvInv.ServiceID
WHERE srv.State > 321
AND srv.State <> 123
GROUP BY srvInv.ObjectID,
srv.State,
srvInv.Direction,
srvInv.ReverseBroken,
srvmn.BBC_ID
) AS A
GROUP BY A.Inventory,
A.ObjectID,
A.State,
A.Broken;
结果正常,但索引视图中不允许派生表。
我尝试在 Sum 中使用 "Over Partition",但结果不正确。
我该如何解决这个问题?
正确结果:
Inventory ObjectID State Broken Sum
------------------------------------------------
NULL 2 500 0 -1
NULL 3 320 1 1
NULL 3 500 0 2
NULL 3 600 0 1
NULL 18 600 0 -1
NULL 20 600 0 -1
1162 20 600 0 1
NULL 24 600 0 1
NULL 26 310 0 -3
NULL 26 320 0 -1
NULL 26 600 0 7
442 26 500 0 8
442 26 500 1 1
442 26 600 0 -5
1162 26 600 0 0
NULL 27 500 0 4
NULL 27 600 0 2
1162 27 600 0 1
1162 28 600 0 3
不正常结果:
Inventory ObjectID State Broken Sum CountLines
-------------------------------------------------------------
NULL 2 500 0 -1 1
NULL 3 500 0 2 2
NULL 3 600 0 1 1
NULL 18 600 0 -1 1
1162 20 600 0 3 3
1162 20 600 0 -2 2
NULL 20 600 0 1 1
NULL 20 600 0 -2 2
NULL 24 600 0 -1 1
NULL 24 600 0 2 2
442 26 600 0 -7 7
NULL 26 600 0 -18 18
1162 26 600 0 1 1
NULL 26 600 0 25 25
442 26 500 1 1 1
442 26 600 0 2 2
1162 26 600 0 -1 1
442 26 500 0 8 8
NULL 27 600 0 -3 3
1162 27 600 0 1 1
您不应在 "Group By"
中使用字段 "srvInv.Direction"请试一试:
SELECT
srvmn.BBC_ID AS Inventory,
srvInv.ObjectID,
srv.State,
SUM(IIF(srvInv.Direction = srvInv.ReverseBroken, 1, 0)) AS Broken,
SUM(IIF(srvInv.Direction = 0, 1, -1)) AS Sum
FROM table1 srvmn
JOIN table2 srv ON srv.ServiceManID = srvmn.ID
JOIN table3 srvInv ON srv.ID = srvInv.ServiceID
WHERE srv.State > 321 AND srv.State <> 123
GROUP BY
srvInv.ObjectID,
srv.State,
srvInv.ReverseBroken,
srvmn.BBC_ID