如何解码 PHP 中的 Java 流

Question

我请求沃尔玛报告API，结果会返回zip文件stream.Refer到API文件，它给出了一个用Java代码实现的例子如下所示：

if (response.getStatus() == Response.Status.OK.getStatusCode() &amp;&amp; response.hasEntity()) {
  InputStream inputStream = (InputStream)response.getEntity();
  try {
    String header = response.getHeaderString("Content-Disposition");
    if(header != null &amp;&amp; !("").equals(header)) {
      if(header.contains("filename")){
        //header value will be something like:
        //attachment; filename=10000000354_2016-01-15T23:09:54.438+0000.zip
        int length = header.length();
        String fileName = header.substring(header.indexOf("filename="),length);
        System.out.println("filenameText " + fileName);
        String [] str = fileName.split("=");
        System.out.println("fileName: " + str[1]);
        //replace "/Users/anauti1/Documents/" below with your values
        File reportFile = new File("/Users/anauti1/Documents/" + str[1].toString());
        OutputStream outStream = new FileOutputStream(reportFile);
        byte[] buffer = new byte[8 * 1024];
        int bytesRead;
        while ((bytesRead = inputStream.read(buffer)) != -1) {
          outStream.write(buffer, 0, bytesRead);
        }
        IOUtils.closeQuietly(inputStream);
        IOUtils.closeQuietly(outStream);
      }
    }
  }
  catch (Exception ex){
    System.out.print("Exception: " + ex.getMessage());
  }
}

但是，如果我使用 php 比如：

try {
                        $header = $resultInfo->getHeader('Content-Disposition');
                        if (!empty($header)) {
                            if (strpos($header, 'filename') !== false) {
                                $filename = substr($header, strpos($header, 'filename'));
                                $str = explode('=', $filename);
                                $body = $resultInfo->getBody();
                                $fp = fopen(storage_path("csv/{$str[1]}"), 'w');
                                fwrite($fp, $body);
                                fclose($fp);
                            }
                        }
                    } catch (\Exception $e) {
                        echo $e->getMessage();
                    }

会下载zip文件，但是文件数据是corrupt.It可能是字节流使用Java传输这样的原因code.It如何转换的问题bytes stream.Could 大家帮帮我好吗？顺便说一下，我已经将部分流剪切如下：

b"PK\x03\x04\x14\x00\x00\x00\x08\x00\x10`‚OI^\x07RÒƒ\x04\x00Óo\x10\x004\x00\x00\x00ItemReport_10001023965_2019-12-02T115111.5040000.csvì½YsÛÈ–.ú~#î\x7F`ì‡>

Headers 像这样：

-headers: array:11 [
            "accept-ranges" => array:1 [
              0 => "bytes"
            ]
            "content-disposition" => array:1 [
              0 => "attachment; filename=ItemReport_10001023965_2019-12-02T115111.5040000.zip"
            ]
            "content-type" => array:1 [
              0 => "application/zip"
            ]
            "x-tb" => array:1 [
              0 => "0"
            ]
            "expires" => array:1 [
              0 => "Wed, 04 Dec 2019 02:33:20 GMT"
            ]
            "cache-control" => array:1 [
              0 => "max-age=0, no-cache, no-store"
            ]
            "pragma" => array:1 [
              0 => "no-cache"
            ]
            "date" => array:1 [
              0 => "Wed, 04 Dec 2019 02:33:20 GMT"
            ]
            "transfer-encoding" => array:1 [
              0 => "chunked"
            ]
            "connection" => array:2 [
              0 => "keep-alive"
              1 => "Transfer-Encoding"
            ]
            "set-cookie" => array:1 [
              0 => "TS0d138f181a7bb55a8f02b54ee05b24ba9b4832fa32c8b0a9c4cb8592e5d1e4d02765d16ec77313d435d3ade8; Path=/; Secure"
            ]
          ]
          -headerNames: array:11 [
            "accept-ranges" => "Accept-Ranges"
            "content-disposition" => "Content-Disposition"
            "content-type" => "Content-Type"
            "x-tb" => "X-Tb"
            "expires" => "Expires"
            "cache-control" => "Cache-Control"
            "pragma" => "Pragma"
            "date" => "Date"
            "transfer-encoding" => "Transfer-Encoding"
            "connection" => "Connection"
            "set-cookie" => "Set-Cookie"
          ]

我刚刚发现 transfer-encoding 是 chuncked.I不确定是不是这个问题？

Answer 1

似乎 Json 已编码，您必须在 php 脚本中使用 json 对其进行解码，因此： json_decode（字符串，数组） string = 您收集的编码响应。 array = True 如果你想要结果数据数组。

2- 使用 header('Content-Type: application/json') （这个 header 最有用在发送或接收响应之前）

3 - 错误处理： json_last_error() json_last_error_msg()

try {
                        $header = $resultInfo->getHeader('Content-Disposition');
                        if (!empty($header)) {
                            if (strpos($header, 'filename') !== false) {
                                $filename = substr($header, strpos($header, 'filename'));
                                $str = explode('=', $filename);
                                $body = $resultInfo->getBody();
                                $fp = fopen(storage_path("csv/{$str[1]}"), 'w');
                                ##uncomment below line if response not valid may help you.                            
                                # header('Content-Type: application/json');
                                $dbody = json_decode($body,true);
                                fwrite($fp, $dbody);
                                fclose($fp);
                            }
                        }
                    } catch (\Exception $e) {
                        echo $e->getMessage();
                    }

希望能有所帮助

Answer 2

问题解决了吗？下面的简单代码对我有用

    $fp = fopen('/your path where you store the zip file/'.$filename, 'w+'); 
    if ($fp == FALSE){ 
      print "File not opened<br>"; 
      exit; 
    }
    fwrite($fp, $response);
    fclose($fp);

$response是API响应的body，将是不可读的格式 $filename zip 文件名来自 header。

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