Golang Exec 命令长输出
Golang Exec Command Long Output
如何从很长的 ping 命令输出中获取 ping 统计信息:
func main() {
cmdout, _ := exec.Command("ping", "127.0.0.1", "-n", "30000").Output()
fmt.Printf("%s\n", cmdout)
}
我只需要这个输出:
Ping statistics for 127.0.0.1:
Packets: Sent = 30000, Received = 30000, Lost = 0 (0% loss),
Approximate round trip times in milli-seconds:
Minimum = 0ms, Maximum = 0ms, Average = 0ms
输出如下:
Reply from 127.0.0.1: bytes=32 time<1ms TTL=128
Reply from 127.0.0.1: bytes=32 time<1ms TTL=128
Reply from 127.0.0.1: bytes=32 time<1ms TTL=128
...............................................
我只想丢弃。我正在考虑将所有这些输出放入一个变量然后解析它直到我得到所需的结果:
output := string(out)
scanner := bufio.NewScanner(strings.NewReader(output))
for scanner.Scan() {
fmt.Println("Line: ", scanner.Text())
regex compile etc...
}
但是,我不确定这是实现该目标的有效模式,通过选择这种方式意味着用大量未使用的数据填充 RAM,这不是我正在看的。我说的对吗?
我认为下面的代码是我需要的:
func main() {
args := "-n 30000 127.0.0.1"
cmd := exec.Command("ping", strings.Split(args, " ")...)
output, _ := cmd.StdoutPipe()
cmd.Start()
scanner := bufio.NewScanner(output)
for scanner.Scan() {
m := scanner.Text()
matchPackets, _ := regexp.MatchString("Packets", m)
matchMinimum, _ := regexp.MatchString("Minimum", m)
if matchPackets {
fmt.Println("Ping statistics for 127.0.0.1")
fmt.Println(m)
}
if matchMinimum {
fmt.Println("Approximate round trip times in milli-seconds:")
fmt.Println(m)
}
}
cmd.Wait()
}
如何从很长的 ping 命令输出中获取 ping 统计信息:
func main() {
cmdout, _ := exec.Command("ping", "127.0.0.1", "-n", "30000").Output()
fmt.Printf("%s\n", cmdout)
}
我只需要这个输出:
Ping statistics for 127.0.0.1:
Packets: Sent = 30000, Received = 30000, Lost = 0 (0% loss),
Approximate round trip times in milli-seconds:
Minimum = 0ms, Maximum = 0ms, Average = 0ms
输出如下:
Reply from 127.0.0.1: bytes=32 time<1ms TTL=128
Reply from 127.0.0.1: bytes=32 time<1ms TTL=128
Reply from 127.0.0.1: bytes=32 time<1ms TTL=128
...............................................
我只想丢弃。我正在考虑将所有这些输出放入一个变量然后解析它直到我得到所需的结果:
output := string(out)
scanner := bufio.NewScanner(strings.NewReader(output))
for scanner.Scan() {
fmt.Println("Line: ", scanner.Text())
regex compile etc...
}
但是,我不确定这是实现该目标的有效模式,通过选择这种方式意味着用大量未使用的数据填充 RAM,这不是我正在看的。我说的对吗?
我认为下面的代码是我需要的:
func main() {
args := "-n 30000 127.0.0.1"
cmd := exec.Command("ping", strings.Split(args, " ")...)
output, _ := cmd.StdoutPipe()
cmd.Start()
scanner := bufio.NewScanner(output)
for scanner.Scan() {
m := scanner.Text()
matchPackets, _ := regexp.MatchString("Packets", m)
matchMinimum, _ := regexp.MatchString("Minimum", m)
if matchPackets {
fmt.Println("Ping statistics for 127.0.0.1")
fmt.Println(m)
}
if matchMinimum {
fmt.Println("Approximate round trip times in milli-seconds:")
fmt.Println(m)
}
}
cmd.Wait()
}