一年中的哪一周使用 bigquery/bigrquery 和 dbplyr？ （相当于 lubridate::week）
Week of year using bigquery / bigrquery and dbplyr? (equivalent of lubridate::week)
我正在尝试使用 bigrquery 和 dbplyr 来获取 week of the year that a date corresponds to（即与 lubridate::week() 相同，即
library(lubridate)
library(dbplyr)
library(bigrquery)
week("2015-08-11")
# [1] 32
但我正在使用 bigrquery 和 dbplyr
到目前为止我尝试了什么
使用lubridate::week() 我明白了
transactions %>%
select(item, date) %>%
mutate(week = week(date)) %>%
collect()
Error: Function not found: week at [1:30] [invalidQuery]
所以我尝试了这个自制的解决方案
transactions %>%
select(item, date) %>%
mutate(week = strftime(date, format = "%V")) %>%
collect()
Error: Syntax error: Expected ")" but got keyword AS at [1:54] [invalidQuery]
In addition: Warning message:
Named arguments ignored for SQL strftime
以及另一个（相当丑陋的）自制解决方案
transactions %>%
select(item, date) %>%
mutate(week = as.numeric((as.Date(date) - as.Date(paste0(substr(date, 1, 4), "-01-01"))), units="days") %/% 7) %>%
collect()
Error in as.numeric((as.Date(date) - as.Date(paste0(substr(date, 1, :
unused argument (units = "days")
但我似乎找不到使用 bigquery 和 dbplyr 获取周数的方法
I cannot seem to find a way to get the week number using bigquery
看起来您正在寻找以下 BigQuery 标准 SQL 函数
EXTRACT(WEEK FROM date)
您可以使用 WEEK 或 WEEK(< WEEKDAY>) 或 ISOWEEK
在此处查看有关日期部分的更多信息https://cloud.google.com/bigquery/docs/reference/standard-sql/date_functions#extract
我正在尝试使用 bigrquery 和 dbplyr 来获取 week of the year that a date corresponds to（即与 lubridate::week() 相同，即
library(lubridate)
library(dbplyr)
library(bigrquery)
week("2015-08-11")
# [1] 32
但我正在使用 bigrquery 和 dbplyr
到目前为止我尝试了什么
使用lubridate::week() 我明白了
transactions %>%
select(item, date) %>%
mutate(week = week(date)) %>%
collect()
Error: Function not found: week at [1:30] [invalidQuery]
所以我尝试了这个自制的解决方案
transactions %>%
select(item, date) %>%
mutate(week = strftime(date, format = "%V")) %>%
collect()
Error: Syntax error: Expected ")" but got keyword AS at [1:54] [invalidQuery]
In addition: Warning message:
Named arguments ignored for SQL strftime
以及另一个（相当丑陋的）自制解决方案
transactions %>%
select(item, date) %>%
mutate(week = as.numeric((as.Date(date) - as.Date(paste0(substr(date, 1, 4), "-01-01"))), units="days") %/% 7) %>%
collect()
Error in as.numeric((as.Date(date) - as.Date(paste0(substr(date, 1, :
unused argument (units = "days")
但我似乎找不到使用 bigquery 和 dbplyr 获取周数的方法
I cannot seem to find a way to get the week number using bigquery
看起来您正在寻找以下 BigQuery 标准 SQL 函数
EXTRACT(WEEK FROM date)
您可以使用 WEEK 或 WEEK(< WEEKDAY>) 或 ISOWEEK
在此处查看有关日期部分的更多信息https://cloud.google.com/bigquery/docs/reference/standard-sql/date_functions#extract