PHP 7.3 警告：count(): 参数必须是数组或实现了Countable的对象

Question

Warning: count(): Parameter must be an array or an object that implements Countable

$tags=locchuoi($request,"<span class='SeoH1'>",'</span>');
for($ll=1;$ll<count($tags)+1;$ll++)
{
    $tag_link =   $tag_link.$tags[$ll].",";
}

Answer 1

print_r($tags);

使用它并检查标签的输出。它可能为空，所以你会像 this.check

 `locchuoi($request,"<span class='SeoH1'>",'</span>');`

此函数返回您需要的准确输出。

Answer 2

简单地将Count替换为!empty你的问题就解决了

$tags=locchuoi($request,"<span class='SeoH1'>",'</span>');
for($ll=1;$ll<=(!empty($tags) ? count($tags) : 0);$ll++)
{
    $tag_link =   $tag_link.$tags[$ll].",";
}

Answer 3

$tags=locchuoi($request,"<span class='SeoH1'>",'</span>');
for($ll=1;$ll<(!empty($tags) ? count($tags)+1 : 0);$ll++)
{
   $tag_link =   $tag_link.$tags[$ll].",";
}

试试这段代码，我只是在 for() 中添加了一些条件，当 $tags 变量为空时 return 0 ，如果不是 return count($tags)+1 .

PHP 7.3 警告：count(): 参数必须是数组或实现了Countable的对象

PHP 7.3 Warning: count(): Parameter must be an array or an object that implements Countable

php

warnings