我正在尝试将 int 值插入到字符串中，而不是 1 我得到 10

Question

我有 1005 个节点，所以我在这里输入 1005 和值 1 到 1005 通过循环 ps。即使我手动输入我得到相同的 print

void call() 
{
    int x;
    cout << "Enter Number of characters";       string s;
    cin >> t;
    cout << "Enter char names :";
    for (int i = 0; i < t; i++) 
    {
        x = i + 1;
        str1 = to_string(x);
        //cin >> str1;
        insertd(str1);
    }
}


void insertd(string n) {
    node *ptr = new node;

    ptr->name = n;

    if (head == NULL) {

        head = ptr;

        last = ptr;

    }

    else {

        last->down = ptr;

        last = ptr;

    }

}

当我在此处使用此部分进行打印时

void print() {
    current = head;
    node *p;
    while (current != NULL) {
        p = current;
        while (p != NULL) {
            cout << p->name << p->weight << "   ";
            p = p->next;
        }
        cout << endl;
        current = current->down;
    }
}

我得到的结果是 10,20,30 而不是 1 ,2,3

Answer 1

如果您使用 std::to_string 进行转换，则不应打印 10 而不是 0。你能试试只打印名字吗？

std::cout << p->name << std::endl

You are certainly having 0 for p->weight.

我正在尝试将 int 值插入到字符串中，而不是 1 我得到 10

I am trying to insert int values into string and instead of 1 i get 10

c++

nodes

adjacency-list