使用 Laravel APi 时搜索 Returns 数据库中的所有数据

Search Returns All Data in Database while using Laravel APi

我正在使用 Laravel 处理 API,我希望能够使用 API 进行搜索,但我无法 这是我的方法

   public function searchapi()
   {

 $search = request()->get('search');

   /* $books = Book::when($search, function ($query, $search) {
       return $query->where('name', 'LIKE', "%{$search}%");
   })
    ->orderBy('created_at', 'desc')
    ->simplepaginate(12); */

  $books = Book::where('name', 'LIKE', "%{$search}%")->Paginate(16);
  $author = Author::where('name', 'LIKE', "%{$search}%")->Paginate(16);
  $genre = Category::where('title', 'LIKE', "%{$search}%")->Paginate(16);



   return Response::json(array(
    'books' => $books, 
    'author'=>$author,
    'genre'=>$genre,
 ));


}

我不知道我做错了什么,因为 returns 使用 postman 搜索时数据库中的所有数据。

我的路线在api.php

Route::get('/search', 'BooksController@searchapi');

更新

我正在使用 post man 进行测试。我通过了 Key=searchvalue=searchterm

方法:

public function searchapi(Request $request)
   {

 $search = request()->get('search');

   /* $books = Book::when($search, function ($query, $search) {
       return $query->where('name', 'LIKE', "%{$search}%");
   })
    ->orderBy('created_at', 'desc')
    ->simplepaginate(12); */

  $books = Book::where('name', 'LIKE', "%{$search}%")->Paginate(16);
  $author = Author::where('name', 'LIKE', "%{$search}%")->Paginate(16);
  $genre = Category::where('title', 'LIKE', "%{$search}%")->Paginate(16);



   return Response::json(array(
    'books' => $books, 
    'author'=>$author,
    'genre'=>$genre,
 ));


}

路线:

Route::post('/search', 'BooksController@searchapi');