列出 Blogger API 的所有帖子
Listing all posts with Blogger API
我正在尝试使用 Blogger API v3:
列出所有博文
<script type="text/javascript">
function handleResponse(response) {
var post_number = Object.keys(response.items).length; //number of posts
for (i=0; i<post_number; i++) {
$('#content').append('<div id="post' + (i+1) + '" class="post"><p></p></div>');
$('.post p').html(Object.keys(response.items[i].title));
}
}
</script>
<script src="https://www.googleapis.com/blogger/v3/blogs/1961645108677548855/posts?callback=handleResponse&key=AIzaSyAJESQB3ddltUcDbZif3LUnX-Gzr18tBRg"></script>
这确实在我的内容 div 后附加了 3 div(因为有 3 个帖子)。但是每一个div的内容是:
<p>
"1"
"2"
"3"
"4"
"5"
</p>
我不知道为什么,尽管我假设 title
是 items[]
的属性。
任何解决方案或线索?
感谢解答!
您应该删除 Object.keys()
并试试这个:
<script type="text/javascript">
function handleResponse(response) {
var post_number = Object.keys(response.items).length; //number of posts
for (i=0; i<post_number; i++) {
$('#content').append('<div id="post' + (i+1) + '" class="post"><p></p></div>');
$('.post p').html(response.items[i].title);
}
}
</script>
<script src="https://www.googleapis.com/blogger/v3/blogs/1961645108677548855/posts?callback=handleResponse&key=AIzaSyAJESQB3ddltUcDbZif3LUnX-Gzr18tBRg"></script>
在你的情况下你不应该使用 Object.keys()
您的请求未使用 maxResults
参数并且检索的帖子数量有限,因此我建议使用 Google JavaScript Client Library - Blogger API 并递归检索博客的所有帖子。
看下面的例子:
<script>
function renderResults(response) {
if (response.items) {
for (var i = 0; i < response.items.length; i++) {
//do whatever you want with the posts of your blog
}
}
if(response.nextPageToken) {
var blogId = 'XXX Your blogId XXX';
var request = gapi.client.blogger.posts.list({
'blogId': blogId,
'pageToken': response.nextPageToken,
'maxResults': 100,
});
request.execute(renderResults);
}
}
function init() {
gapi.client.setApiKey('XXX Get your API Key from https://code.google.com/apis/console XXX');
gapi.client.load('blogger', 'v3', function() {
var blogId = 'XXX Your blogId XXX';
var request = gapi.client.blogger.posts.list({
'blogId': blogId,
'maxResults': 100,
});
request.execute(renderResults);
});
}
</script>
<script src="https://apis.google.com/js/client.js?onload=init"></script>
我正在尝试使用 Blogger API v3:
列出所有博文<script type="text/javascript">
function handleResponse(response) {
var post_number = Object.keys(response.items).length; //number of posts
for (i=0; i<post_number; i++) {
$('#content').append('<div id="post' + (i+1) + '" class="post"><p></p></div>');
$('.post p').html(Object.keys(response.items[i].title));
}
}
</script>
<script src="https://www.googleapis.com/blogger/v3/blogs/1961645108677548855/posts?callback=handleResponse&key=AIzaSyAJESQB3ddltUcDbZif3LUnX-Gzr18tBRg"></script>
这确实在我的内容 div 后附加了 3 div(因为有 3 个帖子)。但是每一个div的内容是:
<p>
"1"
"2"
"3"
"4"
"5"
</p>
我不知道为什么,尽管我假设 title
是 items[]
的属性。
任何解决方案或线索?
感谢解答!
您应该删除 Object.keys()
并试试这个:
<script type="text/javascript">
function handleResponse(response) {
var post_number = Object.keys(response.items).length; //number of posts
for (i=0; i<post_number; i++) {
$('#content').append('<div id="post' + (i+1) + '" class="post"><p></p></div>');
$('.post p').html(response.items[i].title);
}
}
</script>
<script src="https://www.googleapis.com/blogger/v3/blogs/1961645108677548855/posts?callback=handleResponse&key=AIzaSyAJESQB3ddltUcDbZif3LUnX-Gzr18tBRg"></script>
在你的情况下你不应该使用 Object.keys()
您的请求未使用 maxResults
参数并且检索的帖子数量有限,因此我建议使用 Google JavaScript Client Library - Blogger API 并递归检索博客的所有帖子。
看下面的例子:
<script>
function renderResults(response) {
if (response.items) {
for (var i = 0; i < response.items.length; i++) {
//do whatever you want with the posts of your blog
}
}
if(response.nextPageToken) {
var blogId = 'XXX Your blogId XXX';
var request = gapi.client.blogger.posts.list({
'blogId': blogId,
'pageToken': response.nextPageToken,
'maxResults': 100,
});
request.execute(renderResults);
}
}
function init() {
gapi.client.setApiKey('XXX Get your API Key from https://code.google.com/apis/console XXX');
gapi.client.load('blogger', 'v3', function() {
var blogId = 'XXX Your blogId XXX';
var request = gapi.client.blogger.posts.list({
'blogId': blogId,
'maxResults': 100,
});
request.execute(renderResults);
});
}
</script>
<script src="https://apis.google.com/js/client.js?onload=init"></script>