通过 Spring 4 配置时，Quartz Scheduler 不会触发作业

Question

我一直在尝试设置一个小程序，该程序同时使用 Spring 和 Quartz 来安排任务。我没有运气就遵循了其他一些类似的答案。目前我认为我已经全部配置正确，我没有看到更多异常，但我的工作看起来没有开始。

在 Spring 生成的 log.out 中，我在末尾看到以下消息：

2015-06-04T15:46:57.928 DEBUG [org.springframework.core.env.PropertySourcesPropertyResolver] Searching for key 'spring.liveBeansView.mbeanDomain' in [systemProperties] 2015-06-04T15:46:57.929 DEBUG [org.springframework.core.env.PropertySourcesPropertyResolver] Searching for key 'spring.liveBeansView.mbeanDomain' in [systemEnvironment] 2015-06-04T15:46:57.929 DEBUG [org.springframework.core.env.PropertySourcesPropertyResolver] Could not find key 'spring.liveBeansView.mbeanDomain' in any property source. Returning [null]

我会告诉你我的代码...

这是我启动调度程序的class：

public class JobRunner {

    public static void main(String[] args) throws SchedulerException {
        ApplicationContext applicationContext = new AnnotationConfigApplicationContext(WhatsTheTimeConfiguration.class);
        AutowiringSpringBeanJobFactory autowiringSpringBeanJobFactory = new AutowiringSpringBeanJobFactory();
        autowiringSpringBeanJobFactory.setApplicationContext(applicationContext);

        SpringBeanJobFactory springBeanJobFactory = new SpringBeanJobFactory();

        SchedulerFactoryBean schedulerFactoryBean = new SchedulerFactoryBean();
        schedulerFactoryBean.setTriggers(trigger());
        schedulerFactoryBean.setJobFactory(springBeanJobFactory);
        schedulerFactoryBean.start();
    }

    private static SimpleTrigger trigger() {
        return newTrigger()
                .withIdentity("whatsTheTimeJobTrigger", "jobsGroup1")
                .startNow()
                .withSchedule(simpleSchedule()
                        .withIntervalInSeconds(1)
                        .repeatForever())
                .build();
    }

}

我想提一下，如果我使用 schedulerFactoryBean.getScheduler().start() 方法，它会在调度程序上抛出一个空指针异常，这就是我在工厂上调用 start() 的原因。

class AutowiringSpringBeanJobFactory 是从 Whosebug 中的另一个答案复制粘贴而来的。我决定这样做，因为我发现的所有其他答案都只是通过 xml 完成的配置，我不想使用 xml.

public final class AutowiringSpringBeanJobFactory extends SpringBeanJobFactory implements
        ApplicationContextAware {

    private transient AutowireCapableBeanFactory beanFactory;

    @Override
    public void setApplicationContext(final ApplicationContext context) {
        beanFactory = context.getAutowireCapableBeanFactory();
    }

    @Override
    protected Object createJobInstance(final TriggerFiredBundle bundle) throws Exception {
        final Object job = super.createJobInstance(bundle);
        beanFactory.autowireBean(job);
        return job;
    }
}

这是代表我要触发的作业的 class：

@Component
public class WhatsTheTimeManager extends QuartzJobBean {

    @Autowired
    private WhatsTheTime usecase;
    @Autowired
    private LocationRetriever locationDataProvider;

    public WhatsTheTimeManager() {
    }

    @Override
    protected void executeInternal(JobExecutionContext jobExecutionContext) throws JobExecutionException {
        usecase.tellMeWhatsTheTimeIn(locationDataProvider.allLocations());
    }

    public void setUsecase(WhatsTheTime usecase) {
        this.usecase = usecase;
    }

    public void setLocationDataProvider(LocationRetriever locationDataProvider) {
        this.locationDataProvider = locationDataProvider;
    }
}

我的Spring配置是做组件扫描，很简单：

@Configuration
@ComponentScan(basePackages = "com.springpractice")
public class WhatsTheTimeConfiguration {

}

从现在开始，我所拥有的只是一些接口、组件和域对象，但我也会粘贴它们，以防万一我忘记了什么：

public interface LocationRetriever {
    List<String> allLocations();
}

public interface TimeOutputRenderer {
    TimeReport renderReport(String timeInLocation, String location);
}

public interface TimeRetriever {
    String timeFor(String location);
}

@Component
public class LocationRetrieverDataProvider implements LocationRetriever{

    public LocationRetrieverDataProvider() {
    }

    @Override
    public List<String> allLocations() {
        return asList("Europe/London", "Europe/Madrid", "Europe/Moscow", "Asia/Tokyo", "Australia/Melbourne", "America/New_York");
    }
}

@Component
public class TimeOutputRendererDataProvider implements TimeOutputRenderer {

    public TimeOutputRendererDataProvider() {
    }

    @Override
    public TimeReport renderReport(String location, String time) {
        System.out.println(location + " time is " + time);
        return new TimeReport(location, time);
    }
}

@Component
public class TimeRetrieverDataProvider implements TimeRetriever {

    public TimeRetrieverDataProvider() {
    }

    @Override
    public String timeFor(String location) {
        SimpleDateFormat timeInLocation = new SimpleDateFormat("dd-M-yyyy hh:mm:ss a");
        timeInLocation.setTimeZone(TimeZone.getTimeZone(location));
        return timeInLocation.format(new Date());
    }
}

最后一个细节，您可能会感兴趣。我在我的库中使用的版本如下：

石英 2.2.1

spring 4.1.6.RELEASE

当我运行应用程序时，我希望每秒打印这些国家/地区的时间，但它并没有发生。

如果你想克隆代码并自己尝试看看，你可以在这个 git 存储库中找到它（如果你愿意，请随意分叉）：https://github.com/SFRJ/cleanarchitecture

Answer 1

您代码中的主要错误是您没有让 Spring 为您处理日程安排。

虽然您可以在代码中像使用任何其他代码一样使用 Quartz，但与 Spring 集成的想法是告诉 Spring 您想要完成的工作并让 Spring 辛苦你了

为了允许Spring到运行 Quartz 调度，你需要将Job、JobDetail 和Trigger 声明为Bean。

Spring 仅处理通过 Spring 生命周期创建的 Bean（即使用注释或 XML），但如果对象是在代码中使用 new语句。

需要从 JobRunner.java 中删除以下代码：

SpringBeanJobFactory springBeanJobFactory = new SpringBeanJobFactory();

SchedulerFactoryBean schedulerFactoryBean = new SchedulerFactoryBean();
schedulerFactoryBean.setTriggers(trigger());
schedulerFactoryBean.setJobFactory(springBeanJobFactory);
schedulerFactoryBean.start();
...
private static SimpleTrigger trigger() {
    return newTrigger()
            .withIdentity("whatsTheTimeJobTrigger", "jobsGroup1")
            .startNow()
            .withSchedule(simpleSchedule()
                    .withIntervalInSeconds(1)
                    .repeatForever())
            .build();
}

该代码必须重新写入 WhatsTheTimeConfiguration.java，现在是这样的：

@Configuration
@ComponentScan(basePackages = "com.djordje.cleanarchitecture")
public class WhatsTheTimeConfiguration {

    @Bean
    public SchedulerFactoryBean schedulerFactoryBean() {
        SchedulerFactoryBean schedulerFactoryBean = new SchedulerFactoryBean();
        schedulerFactoryBean.setTriggers(trigger());
        schedulerFactoryBean.setJobDetails(jobDetail());
        schedulerFactoryBean.setJobFactory(springBeanJobFactory());
        return schedulerFactoryBean;
    }

    @Bean
    public SpringBeanJobFactory springBeanJobFactory() {
        return new AutowiringSpringBeanJobFactory();
    }

    @Bean
    public JobDetail jobDetail() {
        JobDetailImpl jobDetail = new JobDetailImpl();
        jobDetail.setKey(new JobKey("WhatsTheTime"));
        jobDetail.setJobClass(WhatsTheTimeManager.class);
        jobDetail.setDurability(true);
        return jobDetail;
    }

    @Bean
    public SimpleTrigger trigger() {
        return newTrigger()
                .forJob(jobDetail())
                .withIdentity("whatsTheTimeJobTrigger", "jobsGroup1")
                .startNow()
                .withSchedule(simpleSchedule()
                        .withIntervalInSeconds(1)
                        .repeatForever())
                .build();
    }
}

SchedulerFactoryBean现在是一个Bean，将由Spring处理和初始化，SimpleTrigger和AutowiringSpringBeanJobFactory也是如此。

我添加了缺少的 JobDetail class 并添加了必要的接线到 SimpleTrigger 和 SchedulerFactoryBean。他们都需要知道 JobDetail，这是唯一知道哪个 class 是需要触发的工作 class 的地方。

通过 Spring 4 配置时，Quartz Scheduler 不会触发作业

Quartz Scheduler not triggering the job when configured via Spring 4

java

spring

quartz-scheduler