从列表中的分数元组分配排名

Question

我在一个列表中有三个元组，如果我是正确的话，我正在尝试 return 给定游戏的三个最佳玩家的排名。考虑以下因素：

players_score  = [ ('Joe', 100, 34, 38, 90, 67, 3, 10),
                   ('Bob', 90, 38, 4, 100, 60, 4, 11),
                   ('May', 80, 36, 40, 91, 70, 2, 12),
                   ('Anna', 95, 32, 36, 92, 68, 8, 13) ]

正在打印第一个游戏的结果 returns 以下比分：

[('Joe', 100), ('Bob', 90), ('May', 80), ('Anna', 95)]

但是，我想让程序打印这个：

[ ('Joe', 1), ('Anna', 2), ('Bob', 3) ]

由于乔有 100 分，安娜有 95 分，鲍勃有 90 分。

我正在考虑使用 enumerate()，但我认为首先将元组转换为字典可能会更好，我在代码的最后部分尝试过，但运气不佳。我开始尝试以下方法：

#prints the corresponding score with the player.
game = int(input("Please enter the number of a game: "))
game_score = [ (p[0], p[game]) for p in players_score]
print(game_score)

#prints a list of results ordered from high to low.
score_list = []

for p in players_score:
    score_list.append(p[game])

score_list.sort(reverse=True)
print(score_list)

#prints only the name and the result of the first game
list = [ (name, first) for name, first, second, third, fourth, sixth, seventh, eighth in players_score ]
print(list)

#trying to get a convert from a tuple to a dict.
for name, first, second, third, forth, sixth, seventh, eighth in players_score:
    dict(name, first)

print(dict)

Answer 1

你有这个：

a = [('Joe', 100), ('Bob', 90), ('May', 80), ('Anna', 95)]

尝试使用每个元组的第二个参数对其进行排序：

a = sorted(a, key=lambda x:x[1], reverse=True)

然后：

result = [(v[0], i+1) for i,v in enumerate(a)][0:3]

输出将是：

[('Joe', 1), ('Anna', 2), ('Bob', 3)]

Answer 2

此外，对于第一个答案，您可以将玩家得分转换为字典，以方便之后的操作：

例如：

players_score  = [ ('Joe', 100, 34, 38, 90, 67, 3, 10),
                   ('Bob', 90, 38, 4, 100, 60, 4, 11),
                   ('May', 80, 36, 40, 91, 70, 2, 12),
                   ('Anna', 95, 32, 36, 92, 68, 8, 13) ]

# convert player's scores to dictionary
games = {}
for (player_name, *scores) in players_score:
    for game_no, score in enumerate(scores, 1):
        games.setdefault(game_no, {}).setdefault(player_name, {})
        games[game_no][player_name] = score

# the dictionary "games" will look like:

# {1: {'Anna': 95, 'Bob': 90, 'Joe': 100, 'May': 80},
#  2: {'Anna': 32, 'Bob': 38, 'Joe': 34, 'May': 36},
#  3: {'Anna': 36, 'Bob': 4, 'Joe': 38, 'May': 40},
#  4: {'Anna': 92, 'Bob': 100, 'Joe': 90, 'May': 91},
#  5: {'Anna': 68, 'Bob': 60, 'Joe': 67, 'May': 70},
#  6: {'Anna': 8, 'Bob': 4, 'Joe': 3, 'May': 2},
#  7: {'Anna': 13, 'Bob': 11, 'Joe': 10, 'May': 12}}

game = int(input("Please enter the number of a game: "))

# now print the first three names from the game:

for place, (name, score) in enumerate( sorted(games[game].items(), key=lambda k: k[1], reverse=True)[:3], 1 ): # <-- only first three places
    print('{}. {:<10} {}'.format(place, name, score))

打印：

Please enter the number of a game: 4
1. Bob        100
2. Anna       92
3. May        91

Answer 3

你可以这样做：

import numpy as np

players_score  =np.array([ ('Joe', 100, 34, 38, 90, 67, 3, 10),
                   ('Bob', 90, 38, 4, 100, 60, 4, 11),
                   ('May', 80, 36, 40, 91, 70, 2, 12),
                   ('Anna', 95, 32, 36, 92, 68, 8, 13) ])

players_rank=list(
   map(lambda x: (players_score[x[0], 0], *x[1]+1), 
      enumerate(players_score[:, 1:].argsort(axis=0))
   )
)

输出：

[
   ('Joe', 1, 4, 4, 2, 2, 3, 1), 
   ('Bob', 3, 1, 1, 1, 1, 1, 2), 
   ('May', 2, 3, 2, 3, 4, 2, 3), 
   ('Anna', 4, 2, 3, 4, 3, 4, 4)
]

从列表中的分数元组分配排名

Assign ranking from tuples of scores in list

python

dictionary

tuples

list

enumerate