当列表中有两个连续的相似数字时，如何打破循环？

Question

我想将 break 与 for 循环一起使用，在列表中的任何时候，都可能有与上一个相似的数字。

例如：

x1 = [2,12,43,56,65,34,76,6,77,77,77,77,77,5,6,4,31]
x2 = [2,12,43,56,65,34,76,6,88,88,88,88,88,5,6,4,31]
x3 = [2,12,43,56,65,34,76,6,5,5,5,5,5,5,6,4,31]

如何使用break当i ==77 in x1,i == 88 in x2 and i ==5,这意味着当连续两个值相同时，中断。

注意：我数据比较多，就不打开了。所以，我不知道传感器重复了多少。

我想对值使用索引但失败了。

请帮忙或有什么建议？

Answer 1

存储您处理的最后一个值，如果您再次看到它，您可以从循环中跳出

x1 = [2,12,43,56,65,34,76,6,77,77,77,77,77,5,6,4,31]
x2 = [2,12,43,56,65,34,76,6,88,88,88,88,88,5,6,4,31]
x3 = [2,12,43,56,65,34,76,6,5,5,5,5,5,5,6,4,31]

last_seen = -1

for x in [x1, x2, x3]:
  for current_number in x:
    if current_number == last_seen:
      last_seen = -1
      break

    print current_number.
    last_seen = current_number
  print

回复：https://repl.it/repls/MisguidedReliableNotification

当列表中有两个连续的相似数字时，如何打破循环？

How do I break a loop when there are two consecutive similar numbers in a list?

python

for-loop

list

break

python-2.7