文本抓取的多处理
Multiprocessing with text scraping
我想从页面中抓取 <p>
,因为会有几千个页面,所以我想使用多处理。但是,当我尝试将结果附加到某个变量时它不起作用
我想将抓取的结果附加到 data = []
我为基础网站制作了一个 url_common
,因为有些页面不是以 HTTP 等开头的
from tqdm import tqdm
import faster_than_requests as requests #20% faster on average in my case than urllib.request
import bs4 as bs
def scrape(link, data):
for i in tqdm(link):
if i[:3] !='htt':
url_common = 'https://www.common_url.com/'
else:
url_common = ''
try:
ht = requests.get2str(url_common + str(i))
except:
pass
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
for p in paragraphs:
data.append(p.text)
上面的不起作用,因为 map()
不接受上面的函数
我尝试用另一种方式使用它:
def scrape(link):
for i in tqdm(link):
if i[:3] !='htt':
url_common = 'https://www.common_url.com/'
else:
url_common = ''
try:
ht = requests.get2str(url_common + str(i))
except:
pass
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
for p in paragraphs:
print(p.text)
from multiprocessing import Pool
p = Pool(10)
links = ['link', 'other_link', 'another_link']
data = p.map(scrape, links)
我在使用上面的函数时遇到这个错误:
Traceback (most recent call last):
File "C:\ProgramData\Anaconda3\lib\multiprocessing\process.py", line 297, in _bootstrap
self.run()
File "C:\ProgramData\Anaconda3\lib\multiprocessing\process.py", line 99, in run
self._target(*self._args, **self._kwargs)
File "C:\ProgramData\Anaconda3\lib\multiprocessing\pool.py", line 110, in worker
task = get()
File "C:\ProgramData\Anaconda3\lib\multiprocessing\queues.py", line 354, in get
return _ForkingPickler.loads(res)
AttributeError: Can't get attribute 'scrape' on <module '__main__' (built-in)>
我还没有想出一种方法来使用 Pool
并同时将抓取的结果附加到给定变量
编辑
我稍微改变一下,看看它在哪里停止:
def scrape(link):
for i in tqdm(link):
if i[:3] !='htt':
url_common = 'https://www.investing.com/'
else:
url_common = ''
try: #tries are always halpful with url as you never know
ht = requests.get2str(url_common + str(i))
except:
pass
print('works1')
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
print('works2')
for p in paragraphs:
print(p.text)
links = ['link', 'other_link', 'another_link']
scrape(links)
#WORKS PROPERLY AND PRINTS EVERYTHING
if __name__ == '__main__':
p = Pool(5)
print(p.map(scrape, links))
#DOESN'T WORK, NOTHING PRINTS. Error like above
您使用的 map
功能不正确。
它遍历 iterable 的每个元素并在每个元素上调用函数。
您可以看到地图函数执行如下操作:
to_be_mapped = [1, 2, 3]
mapped = []
def mapping(x): # <-- note that the mapping accepts a single value
return x**2
for item in to_be_mapped:
res = mapping(item)
mapped.append(res)
因此,为了解决您的问题,请删除最外层的 for 循环,因为迭代由 map 函数处理
def scrape(link):
if link[:3] !='htt':
url_common = 'https://www.common_url.com/'
else:
url_common = ''
try:
ht = requests.get2str(url_common + str(link))
except:
pass
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
for p in paragraphs:
print(p.text)
我想从页面中抓取 <p>
,因为会有几千个页面,所以我想使用多处理。但是,当我尝试将结果附加到某个变量时它不起作用
我想将抓取的结果附加到 data = []
我为基础网站制作了一个 url_common
,因为有些页面不是以 HTTP 等开头的
from tqdm import tqdm
import faster_than_requests as requests #20% faster on average in my case than urllib.request
import bs4 as bs
def scrape(link, data):
for i in tqdm(link):
if i[:3] !='htt':
url_common = 'https://www.common_url.com/'
else:
url_common = ''
try:
ht = requests.get2str(url_common + str(i))
except:
pass
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
for p in paragraphs:
data.append(p.text)
上面的不起作用,因为 map()
不接受上面的函数
我尝试用另一种方式使用它:
def scrape(link):
for i in tqdm(link):
if i[:3] !='htt':
url_common = 'https://www.common_url.com/'
else:
url_common = ''
try:
ht = requests.get2str(url_common + str(i))
except:
pass
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
for p in paragraphs:
print(p.text)
from multiprocessing import Pool
p = Pool(10)
links = ['link', 'other_link', 'another_link']
data = p.map(scrape, links)
我在使用上面的函数时遇到这个错误:
Traceback (most recent call last):
File "C:\ProgramData\Anaconda3\lib\multiprocessing\process.py", line 297, in _bootstrap
self.run()
File "C:\ProgramData\Anaconda3\lib\multiprocessing\process.py", line 99, in run
self._target(*self._args, **self._kwargs)
File "C:\ProgramData\Anaconda3\lib\multiprocessing\pool.py", line 110, in worker
task = get()
File "C:\ProgramData\Anaconda3\lib\multiprocessing\queues.py", line 354, in get
return _ForkingPickler.loads(res)
AttributeError: Can't get attribute 'scrape' on <module '__main__' (built-in)>
我还没有想出一种方法来使用 Pool
并同时将抓取的结果附加到给定变量
编辑
我稍微改变一下,看看它在哪里停止:
def scrape(link):
for i in tqdm(link):
if i[:3] !='htt':
url_common = 'https://www.investing.com/'
else:
url_common = ''
try: #tries are always halpful with url as you never know
ht = requests.get2str(url_common + str(i))
except:
pass
print('works1')
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
print('works2')
for p in paragraphs:
print(p.text)
links = ['link', 'other_link', 'another_link']
scrape(links)
#WORKS PROPERLY AND PRINTS EVERYTHING
if __name__ == '__main__':
p = Pool(5)
print(p.map(scrape, links))
#DOESN'T WORK, NOTHING PRINTS. Error like above
您使用的 map
功能不正确。
它遍历 iterable 的每个元素并在每个元素上调用函数。
您可以看到地图函数执行如下操作:
to_be_mapped = [1, 2, 3]
mapped = []
def mapping(x): # <-- note that the mapping accepts a single value
return x**2
for item in to_be_mapped:
res = mapping(item)
mapped.append(res)
因此,为了解决您的问题,请删除最外层的 for 循环,因为迭代由 map 函数处理
def scrape(link):
if link[:3] !='htt':
url_common = 'https://www.common_url.com/'
else:
url_common = ''
try:
ht = requests.get2str(url_common + str(link))
except:
pass
parsed = bs.BeautifulSoup(ht,'lxml')
paragraphs = parsed.find_all('p')
for p in paragraphs:
print(p.text)