如何优化在 Google Sheet 中跨多个选项卡提取多个文本比较结果？ (QUERY vs FILTER vs 其他函数)

Question

这里很新，我试图找到进一步优化一组 sheets 函数的最佳方法。

起始函数本质上是 26 个堆叠过滤函数，用于引用包含名称（字符串）下方的单个单元格，找到与这些单元格中的名称关联的 ID，从 "ref" sheet，并创建一个包含这些 ID 的 url。删除机密数据的函数：

=HYPERLINK(CONCATENATE("https://url.com/stuff?ids=",if(isna(filter(ref!$B:$B,ref!$A:$A=B3))=true,"",filter(ref!$B:$B,ref!$A:$A=B3)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B4))=true,"",filter(ref!$B:$B,ref!$A:$A=B4)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B5))=true,"",filter(ref!$B:$B,ref!$A:$A=B5)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B6))=true,"",filter(ref!$B:$B,ref!$A:$A=B6)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B7))=true,"",filter(ref!$B:$B,ref!$A:$A=B7)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B8))=true,"",filter(ref!$B:$B,ref!$A:$A=B8)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B9))=true,"",filter(ref!$B:$B,ref!$A:$A=B9)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B10))=true,"",filter(ref!$B:$B,ref!$A:$A=B10)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B11))=true,"",filter(ref!$B:$B,ref!$A:$A=B11)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B12))=true,"",filter(ref!$B:$B,ref!$A:$A=B12)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B13))=true,"",filter(ref!$B:$B,ref!$A:$A=B13)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B14))=true,"",filter(ref!$B:$B,ref!$A:$A=B14)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B15))=true,"",filter(ref!$B:$B,ref!$A:$A=B15)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B16))=true,"",filter(ref!$B:$B,ref!$A:$A=B16)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B17))=true,"",filter(ref!$B:$B,ref!$A:$A=B17)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B18))=true,"",filter(ref!$B:$B,ref!$A:$A=B18)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B19))=true,"",filter(ref!$B:$B,ref!$A:$A=B19)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B20))=true,"",filter(ref!$B:$B,ref!$A:$A=B20)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B21))=true,"",filter(ref!$B:$B,ref!$A:$A=B21)),",",if(isna(filter(ref!$B:$B,ref!$A:$A=B22))=true,"",filter(ref!$B:$B,ref!$A:$A=B22)),"&morestuff=true"),"Group A")

我能做的最好的优化是在一个单元格 (B1) 中使用 TEXTJOIN 中的此 QUERY 函数编译 ID：

=TEXTJOIN(",",TRUE, QUERY(ref!$A:$B, "select B where A = '"&B3&"' or A = '"&B4&"' or A = '"&B5&"' or A = '"&B6&"' or A = '"&B7&"' or A = '"&B8&"' or A = '"&B9&"' or A = '"&B10&"' or A = '"&B11&"' or A = '"&B12&"' or A = '"&B13&"' or A = '"&B14&"' or A = '"&B15&"' or A = '"&B16&"' or A = '"&B17&"' or A = '"&B18&"' or A = '"&B19&"' or A = '"&B20&"' or A = '"&B21&"' or A = '"&B22&"' or A = '"&B23&"' or A = '"&B24&"' or A = '"&B25&"' or A = '"&B26&"' or A = '"&B27&"' or A = '"&B28&"' or A = '"&B29&"' "))

然后在另一个单元格 (B2) 中生成 url，引用 B1 的 ID：

=HYPERLINK(CONCATENATE("https://url.com/stuff?ids=", ",", B1, "&morestuff=true"), "Group A")

然后我将这些复制到 B-Z 组

我尝试了堆叠在 ARRAYFORMULA 中的 FILTER 的多种变体，但我无法让它工作。我不确定是否应该使用某种语法来更好地处理我不太了解的匹配文本。简单地按首字母匹配不是一种选择，因为有些名称不符合 "ref" sheet 中包含的分组的条件以用于其他数据集中。

所以我的问题真的是：有没有更简单的编译方法，我不必单独引用每个单元格来匹配 "ref" sheet？

以我正在使用的 sheet 为例，这个 link 应该可以工作： https://docs.google.com/spreadsheets/d/1ykSldWyQnPcar9G21ljLOzm3dWC1i82kMaQJuSKHajc/edit?usp=sharing

Answer 1

只需使用另一个 textjoin 构造您的查询字符串，如下所示：

="select B"&if(counta(B3:B)=0,""," where A='")&textjoin("' or A='",true,B3:B)

这不仅比手动键入每个单元格短得多，而且还会根据需要无限向下扩展。