获取代码的执行时间 x 次数

Question

我想做的是运行这个程序，得到它的执行时间，然后再继续做9次。我将如何迭代它以让它打印出 10 个不同的执行时间？我不太确定我需要如何构建程序才能完成此任务。

import time
start_time = time.time()


def fibonacci():
    previous_num, result = 0, 1
    user = 1000
    iteration = 10
    while len(str(result)) < user:
        previous_num, result = result, previous_num + result
        while iteration != 0:
            iteration -= 1
            end = time.time()
            print(start_time - end)
    return result


print(fibonacci())
print("--- %s seconds ---" % (time.time() - start_time))

Answer 1

您需要做的就是创建一个 for 循环并将您的代码放入其中。

import time

def fibonacci(start_time):
    previous_num, result = 0, 1
    user = 1000
    iteration = 10
    while len(str(result)) < user:
        previous_num, result = result, previous_num + result
        while iteration != 0:
            iteration -= 1
            end = time.time()
            print(start_time - end)
    return result

for i in range(0, 10):
    start_time = time.time()
    print(fibonacci(start_time))
    print("--- %s seconds ---" % (time.time() - start_time))

获取代码的执行时间 x 次数

Get execution time of code x amount of times

python

iteration

execution-time