Swagger-ui 扁平化查询参数中的对象，但生成的 angular 客户端不会

Question

我的 spring 启动应用程序中有以下 Rest 函数

@SecuredMaster
@GetMapping(path = "/mitarbeiter")
@Operation(security = {@SecurityRequirement(name = "jwt")})
public Page<MitarbeiterListRow> getMitarbeiter(Pageable pageable, @RequestParam(defaultValue = "") String query) {
    return mitarbeiterRepository.findAllByUsernameContainingIgnoreCaseOrEmailContainingIgnoreCase(pageable, query, query);
}

我使用 springdoc 生成 openapi3 yaml

// generate api docs
implementation 'org.springdoc:springdoc-openapi-ui:1.2.18'
implementation 'org.springdoc:springdoc-openapi-data-rest:1.2.18'

生成的 yaml 看起来像这样

然后我生成一个angular客户端

java -jar swagger-codegen-cli.jar generate -i http://localhost:8080/apidocs/v3/api-docs -l typescript-angular -o ../frontend/src/generated/swagger

生成的客户端如下所示

/**
 * 
 * 
 * @param pageable 
 * @param query 
 * @param observe set whether or not to return the data Observable as the body, response or events. defaults to returning the body.
 * @param reportProgress flag to report request and response progress.
 */
public getMitarbeiter(pageable: Pageable, query?: string, observe?: 'body', reportProgress?: boolean): Observable<PageMitarbeiterListRow>;
public getMitarbeiter(pageable: Pageable, query?: string, observe?: 'response', reportProgress?: boolean): Observable<HttpResponse<PageMitarbeiterListRow>>;
public getMitarbeiter(pageable: Pageable, query?: string, observe?: 'events', reportProgress?: boolean): Observable<HttpEvent<PageMitarbeiterListRow>>;
public getMitarbeiter(pageable: Pageable, query?: string, observe: any = 'body', reportProgress: boolean = false ): Observable<any> {

    if (pageable === null || pageable === undefined) {
        throw new Error('Required parameter pageable was null or undefined when calling getMitarbeiter.');
    }


    let queryParameters = new HttpParams({encoder: new CustomHttpUrlEncodingCodec()});
    if (pageable !== undefined && pageable !== null) {
        queryParameters = queryParameters.set('pageable', <any>pageable);
    }
    if (query !== undefined && query !== null) {
        queryParameters = queryParameters.set('query', <any>query);
    }

    let headers = this.defaultHeaders;

    // authentication (jwt) required
    if (this.configuration.accessToken) {
        const accessToken = typeof this.configuration.accessToken === 'function'
            ? this.configuration.accessToken()
            : this.configuration.accessToken;
        headers = headers.set('Authorization', 'Bearer ' + accessToken);
    }
    // to determine the Accept header
    let httpHeaderAccepts: string[] = [
        '*/*'
    ];
    const httpHeaderAcceptSelected: string | undefined = this.configuration.selectHeaderAccept(httpHeaderAccepts);
    if (httpHeaderAcceptSelected != undefined) {
        headers = headers.set('Accept', httpHeaderAcceptSelected);
    }

    // to determine the Content-Type header
    const consumes: string[] = [
    ];

    return this.httpClient.get<PageMitarbeiterListRow>(`${this.basePath}/mitarbeiter`,
        {
            params: queryParameters,
            withCredentials: this.configuration.withCredentials,
            headers: headers,
            observe: observe,
            reportProgress: reportProgress
        }
    );
}

当我使用生成的服务时，它会发出这样的请求：

但是当我使用 swagger 时 UI 它工作正常

为什么 swagger-ui 发出正确的请求而生成的 angular-client 却没有？

Answer 1

这是 typescript-angular 生成器的问题：

https://github.com/OpenAPITools/openapi-generator/issues/4404

已经创建了一个 Pull Request 来解决这个问题，建议您观看：

https://github.com/OpenAPITools/openapi-generator/pull/4407

在此期间，您可以尝试使用类似于 springdoc-openapi-data-rest 中可用的 @PageableAsQueryParam 注释来解决问题。也就是说，您可以在 Spring 控制器方法上使用 @Parameters 并在方法参数本身上使用 @Parameter(hidden = true) 来手动重新定义文档。

这很糟糕，但这是 Pull Request 通过之前的最佳解决方案。

对于您编写的方法，修复会相当简单，只需添加 @PageableAsQueryParam 和 @Parameter(hidden = true):

@PageableAsQueryParam
@SecuredMaster
@GetMapping(path = "/mitarbeiter")
@Operation(security = {@SecurityRequirement(name = "jwt")})
public Page<MitarbeiterListRow> getMitarbeiter(@Parameter(hidden = true) Pageable pageable, @RequestParam(defaultValue = "") String query) {
    return mitarbeiterRepository.findAllByUsernameContainingIgnoreCaseOrEmailContainingIgnoreCase(pageable, query, query);
}

Swagger-ui 扁平化查询参数中的对象，但生成的 angular 客户端不会

Swagger-ui flattens object in query params, but the generated angular client doesn't

angular

swagger

swagger-codegen

springdoc