如何避免 "on_press" 侦听器事件循环？

Question

我正在写一段非常简单的代码。

我想听键盘。
当我按 F11 时，消息 "Activated..." 必须显示一次。
当我再次按 F11 时，消息 "Deactivated..." 必须显示，而且只显示一次。
等等...
当我按下 F12 时，我希望监听器停止。

这是我的一段代码，当我按 F11 时，我很难找到正确的实现来避免常量循环 ("Activated... Deactivated... Activated... Deactivated...")。

此外，欢迎任何关于更好的实现、更先进、更 pythonic 的建议！

# -*- coding: utf-8 -*-

from pynput import keyboard

is_active = False

def on_press(key):
    global is_active
    # Activate/Deactivate when pressing F11
    if key == keyboard.Key.f11:
        if is_active:
            is_active = False
            print("Deactivate...")
        else:
            is_active = True
            print("Activate...")
    # Stop "on_press" listener
    if key == keyboard.Key.f12:
        return False

with keyboard.Listener(on_press=on_press) as listener:
    listener.join()

Answer 1

您将要使用

with keyboard.Listener(on_press=on_press, on_release=on_release) as listener:
    listener.join()

When you hold down on a key you will get multiple events just like if you hold down the aaaaaaaaaaaaaaaaaaaaaaaaaaa key without letting up.您需要设置一个锁定机制，在第一次按下时您不会让它再次发生，直到您释放键。

修改后的代码：

# -*- coding: utf-8 -*-

from pynput import keyboard

is_active = False
is_f11_pressed = False

def on_press(key):
    global is_f11_pressed
    global is_active
    # Activate/Deactivate when pressing F11
    if key == keyboard.Key.f11 and not is_f11_pressed:
        is_f11_pressed = True
        if is_active:
            is_active = False
            print("Deactivate...")
        else:
            is_active = True
            print("Activate...")
    # Stop "on_press" listener
    if key == keyboard.Key.f12:
        return False

def on_release(key):
    global is_f11_pressed
    if key == keyboard.Key.f11:
        is_f11_pressed = False

with keyboard.Listener(on_press=on_press, on_release=on_release) as listener:
    listener.join()

如何避免 "on_press" 侦听器事件循环？

How to avoid loop on "on_press" listener event?

python

listener

pynput

onpress