将 BIGNUM 转换为原始二进制文件
Convert BIGNUM into raw binary file
我想使用 BIGNUM 的 BN_bn2bin 函数将这个十六进制字符串转换成原始二进制文件
BN_hex2bn(&asn1hash, "3031300D060960864801650304020105000420BC5F9353CBB9DCAE86B9F8F68C1C95856DB836ACA2E00C9319716CDF4DD0F5BA");
char *buf = (unsigned char *)malloc(BN_num_bytes(asn1hash));
BN_bn2bin(asn1hash, buf);
FILE *fp;
fp = fopen("ASn1Hash","wb+");
fputs(buf, fp);
fclose(fp);
但为什么只有“30 31 30 0D 06 09 60 86 48 01 65 03 04 02 01 05”输出到文件中?
感谢修复代码
BN_hex2bn(&asn1hash, "3031300D060960864801650304020105000420BC5F9353CBB9DCAE86B9F8F68C1C95856DB836ACA2E00C9319716CDF4DD0F5BA");
int num_bytes = BN_num_bytes(asn1hash);
char *buf = (unsigned char *)malloc(num_bytes);
BN_bn2bin(asn1hash, buf);
FILE *fp;
fp = fopen("ASn1Hash","wb+");
fwrite(buf, 1, num_bytes, fp);
fclose(fp);
我想使用 BIGNUM 的 BN_bn2bin 函数将这个十六进制字符串转换成原始二进制文件
BN_hex2bn(&asn1hash, "3031300D060960864801650304020105000420BC5F9353CBB9DCAE86B9F8F68C1C95856DB836ACA2E00C9319716CDF4DD0F5BA");
char *buf = (unsigned char *)malloc(BN_num_bytes(asn1hash));
BN_bn2bin(asn1hash, buf);
FILE *fp;
fp = fopen("ASn1Hash","wb+");
fputs(buf, fp);
fclose(fp);
但为什么只有“30 31 30 0D 06 09 60 86 48 01 65 03 04 02 01 05”输出到文件中?
感谢修复代码
BN_hex2bn(&asn1hash, "3031300D060960864801650304020105000420BC5F9353CBB9DCAE86B9F8F68C1C95856DB836ACA2E00C9319716CDF4DD0F5BA");
int num_bytes = BN_num_bytes(asn1hash);
char *buf = (unsigned char *)malloc(num_bytes);
BN_bn2bin(asn1hash, buf);
FILE *fp;
fp = fopen("ASn1Hash","wb+");
fwrite(buf, 1, num_bytes, fp);
fclose(fp);