使用当前运行进程连接到运行 Jupyter 内核

Question

周末我在 Jupyter notebook 中进行了一些长时间的处理运行，但浏览器 window 在某个时候关闭了。根据 this answer, the process shouldn't have been canceled, but whatever output I would have gotten would be lost. This is okay, as I only need access to the resulting objects from the process. My goal is to connect to the running kernel in the console, and work from there. According to Jupyter's documentation，我应该可以用

做到这一点

jupyter console --existing

但是在运行这并挂起一分钟后，我得到以下内容

Traceback (most recent call last):
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_console/ptshell.py", line 323, in init_kernel_info
    reply = self.client.get_shell_msg(timeout=1)
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_client/client.py", line 77, in get_shell_msg
    return self.shell_channel.get_msg(*args, **kwargs)
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_client/blocking/channels.py", line 57, in get_msg
    raise Empty
queue.Empty

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/anaconda/envs/py35/bin/jupyter-console", line 11, in <module>
    sys.exit(main())
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_core/application.py", line 267, in launch_instance
    return super(JupyterApp, cls).launch_instance(argv=argv, **kwargs)
  File "/anaconda/envs/py35/lib/python3.5/site-packages/traitlets/config/application.py", line 657, in launch_instance
    app.initialize(argv)
  File "<decorator-gen-116>", line 2, in initialize
  File "/anaconda/envs/py35/lib/python3.5/site-packages/traitlets/config/application.py", line 87, in catch_config_error
    return method(app, *args, **kwargs)
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_console/app.py", line 141, in initialize
    self.init_shell()
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_console/app.py", line 114, in init_shell
    client=self.kernel_client,
  File "/anaconda/envs/py35/lib/python3.5/site-packages/traitlets/config/configurable.py", line 412, in instance
    inst = cls(*args, **kwargs)
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_console/ptshell.py", line 272, in __init__
    self.init_kernel_info()
  File "/anaconda/envs/py35/lib/python3.5/site-packages/jupyter_console/ptshell.py", line 326, in init_kernel_info
    raise RuntimeError("Kernel didn't respond to kernel_info_request")
RuntimeError: Kernel didn't respond to kernel_info_request

发生这种情况是因为我的运行长进程仍在内核上运行，还是可能存在其他问题？当上述过程完成后，我是否可以使用上述命令按预期连接？

Answer 1

解决方案*击鼓声*：

我只需要运行

jupyter console --existing

在我所在的同一目录下运行

jupyter notebook

使用当前 运行 进程连接到 运行 Jupyter 内核

Connecting to a running Jupyter kernel with a currently running process

python

jupyter

jupyter-console

使用当前运行进程连接到运行 Jupyter 内核