为什么 Apache mod_rewrite 删除 uri 部分？

Question

我正在尝试将 Apache 配置为我们的 websoket 服务器 http://localhost:8000（在同一个 OS 上）的加密代理 https://chat.example.com。我根据官方文档启用了 mod_proxy、mod_proxy_http、mod_proxy_wstunnel、mod_rewrite 和 mod_ssl。然后我向 https://chat.example.com/connection/info?t=123144343 发出常规 https GET 请求，但 Apache 将其重写为 http://localhost:8000/?t=123144343 而不是 http://localhost:8000/connection/info?t=123144343。为什么？

<VirtualHost *:443>

    ServerAdmin admin@example.com
    ServerName chat.example.com

    RewriteEngine On

    RewriteCond %{HTTP:Upgrade} =websocket [NC]
    RewriteRule ^(.*)$ ws://localhost:8000/ [P,L]
    RewriteCond %{HTTP:Upgrade} !=websocket [NC]
    RewriteRule ^(.*)$ http://localhost:8000/ [P,L]

    ProxyRequests Off
    ProxyPreserveHost On

    SSLEngine on
    SSLProtocol +TLSv1 +TLSv1.1 +TLSv1.2 +TLSv1.3
    SSLCertificateFile /etc/ssl/certs/example.com.crt
    SSLCertificateKeyFile /etc/ssl/private/example.com.key
    SSLCertificateChainFile /etc/ssl/certs/example.com-chain.crt

    LogLevel rewrite:trace7
    ErrorLog /var/log/example.com/chat_error.log
    CustomLog /var/log/example.com/chat_access.log io

</VirtualHost>


[Wed Dec 25 18:57:16.057448 2019] [rewrite:trace2] [pid 9604:tid 140105269184256] mod_rewrite.c(483): init rewrite engine with requested uri /connection/info, referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057523 2019] [rewrite:trace3] [pid 9604:tid 140105269184256] mod_rewrite.c(483): applying pattern '^(.*)$' to uri '/connection/info', referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057566 2019] [rewrite:trace4] [pid 9604:tid 140105269184256] mod_rewrite.c(483): RewriteCond: input='' pattern='=websocket' [NC] => not-matched, referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057600 2019] [rewrite:trace3] [pid 9604:tid 140105269184256] mod_rewrite.c(483): applying pattern '^(.*)$' to uri '/connection/info', referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057637 2019] [rewrite:trace4] [pid 9604:tid 140105269184256] mod_rewrite.c(483): RewriteCond: input='' pattern='!=websocket' [NC] => matched, referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057670 2019] [rewrite:trace2] [pid 9604:tid 140105269184256] mod_rewrite.c(483): rewrite '/connection/info' -> 'http://localhost:8000/', referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057702 2019] [rewrite:trace2] [pid 9604:tid 140105269184256] mod_rewrite.c(483): forcing proxy-throughput with http://localhost:8000/, referer: https://example.com/personal/chats
[Wed Dec 25 18:57:16.057735 2019] [rewrite:trace1] [pid 9604:tid 140105269184256] mod_rewrite.c(483): go-ahead with proxy request proxy:http://localhost:8000/ [OK], referer: https://example.com/personal/chats

Answer 1

RewriteCond %{HTTP:Upgrade} =websocket [NC]
RewriteRule ^(.*)$ ws://localhost:8000/ [P,L]
RewriteCond %{HTTP:Upgrade} !=websocket [NC]
RewriteRule ^(.*)$ http://localhost:8000/ [P,L]

您正在使用 RewriteRule 模式捕获 URL 路径，即。 (.*)。但是，您没有在替换中使用这个捕获的 URL 路径，而是简单地重写到文档根目录：http://localhost:8000/。查询字符串被隐式复制到替换。

您需要使用 </code> 反向引用将捕获的 URL 路径包含在 <em> 替换 </em> 中。例如：</p> <pre><code>RewriteCond %{HTTP:Upgrade} =websocket [NC] RewriteRule ^(.*)$ ws://localhost:8000 [P,L] RewriteCond %{HTTP:Upgrade} !=websocket [NC] RewriteRule ^(.*)$ http://localhost:8000 [P,L]

请注意，在 virtualhost 上下文中，与 RewriteRule 模式匹配的 URL 路径是root-relative 并包含斜杠前缀，因此斜杠不应包含在 susbtitution 中（除非从捕获的模式中省略）。

如果这不起作用，请尝试使用 REQUEST_URI 服务器变量：

RewriteCond %{HTTP:Upgrade} =websocket [NC]
RewriteRule ^ ws://localhost:8000%{REQUEST_URI} [P,L]
RewriteCond %{HTTP:Upgrade} !=websocket [NC]
RewriteRule ^ http://localhost:8000%{REQUEST_URI} [P,L]

编辑： 尽管我从问题历史记录中看到（令我感到惊讶的是我最初没有看到这一点），但令人困惑的是，您原始问题中的代码块已经包括反向引用，它只是在您最近编辑之后才被删除？！（虽然，根据它的实现方式，它会在 URl-路径的开头导致双斜杠。）

为什么 Apache mod_rewrite 删除 uri 部分？

Why does Apache mod_rewrite remove the uri part?

mod-rewrite

apache2