在同一 windows java 中显示多个文本

Question

我想在同一个 windows 中显示很多文本，但只显示最后一个文本，有我的 2 class :


import Test.Graph;
import javax.swing.JFrame;


public class InterfaceGraphique extends JFrame {

    private static final long serialVersionUID = 1L;


     public InterfaceGraphique() {
        this.setTitle("My first Window");
        this.setSize(800,1000);
        this.setLocationRelativeTo(null);
        this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        this.setContentPane(new Graph("test 1", 150,300,"erreur"));
        this.setContentPane(new Graph("test 2 ", 250,400,"normal"));
        this.setContentPane(new Graph("test3", 350,500,"valide"));


        this.setVisible(true);


    }

}

import java.awt.Graphics;
import javax.swing.JPanel;
import java.awt.Color;
import java.awt.Font;

public class Graph extends JPanel {
    private static final long serialVersionUID = 1L;
    private String fichier;
    private int x;
    private int y;
    String etat;

    public Graph(String fichier, int x, int y, String etat) {
        this.fichier = fichier;
        this.x = x;
        this.y = y;
        this.etat= etat;
    }

    @Override
    public void paintComponent(Graphics g){

        System.out.println("Je suis exécutée !"); 

        if(etat.contentEquals("erreur")) {
            Font font = new Font("Courier", Font.BOLD, 20);
            g.setFont(font);
            g.setColor(Color.red); 
        }
        if(etat.contentEquals("normal")) {
            Font font = new Font("Courier", Font.BOLD, 20);
            g.setFont(font);
            g.setColor(Color.black); 
        }
        if(etat.contentEquals("valide")) {
            Font font = new Font("Courier", Font.BOLD, 20);
            g.setFont(font);
            g.setColor(Color.green); 
        }
        g.drawString(fichier, x, y);

      }

    public static void main(String[] args){
        @SuppressWarnings("unused")
        InterfaceGraphique ig = new InterfaceGraphique();



    }
}

当我编译测试时 class 我有一个 window 只显示 "test 3" 为绿色。感谢您的帮助，抱歉英语不好。 PS：我是 JAVA 的新手，尤其是 GUI 方面的新手，所以您可以告诉我其他错误以解决，谢谢！

Answer 1

问题是下面的代码行实际上替换了 ContentPane：

this.setContentPane(new Graph("test 1", 150,300,"erreur"));
this.setContentPane(new Graph("test 2 ", 250,400,"normal"));
this.setContentPane(new Graph("test3", 350,500,"valide"));

第一行设置为"erreur", 然后第二个将其替换为 "normal"， thrid 再次将其替换为 "valide"

您看到 "valide" 的结果只是因为它是当前值和上次替换值。

您将需要一个 class 可以容纳 "Graph" 的数组或 ArrayList。

顺便说一句：欢迎来到 Java..!!

这里是 classes:

import javax.swing.JFrame;

public class InterfaceGraphique extends JFrame{

private static final long serialVersionUID = 1L;


public InterfaceGraphique() {
    this.setTitle("My first Window");
    this.setSize(800, 1000);
    this.setLocationRelativeTo(null);
    this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

    // First Grapth Object
    Graph graph = new Graph();

    // Create points;
    Point point1 = new Point("test 1", 150, 300, "erreur");
    Point point2 = new Point("test 2 ", 250, 400, "normal");
    Point point3 = new Point("test3", 350, 500, "valide");

    graph.addPoint(point1);
    graph.addPoint(point2);
    graph.addPoint(point3);

    this.setContentPane(graph);

    this.setVisible(true);
}
}

public class Point {

private String fichier;
private int x;
private int y;
private String etat;

public Point(String fichier, int x, int y, String etat) {
    this.fichier = fichier;
    this.x = x;
    this.y = y;
    this.etat= etat;
}

public String getFichier() {
    return fichier;
}

public void setFichier(String fichier) {
    this.fichier = fichier;
}

public int getX() {
    return x;
}

public void setX(int x) {
    this.x = x;
}

public int getY() {
    return y;
}

public void setY(int y) {
    this.y = y;
}

public String getEtat() {
    return etat;
}

public void setEtat(String etat) {
    this.etat = etat;
}
}

import java.awt.Color;
import java.awt.Font;
import java.awt.Graphics;
import java.util.ArrayList;
import java.util.List;

import javax.swing.JPanel;

public class Graph extends JPanel{

List<Point> points = new ArrayList<Point>();

@Override
public void paintComponent(Graphics g){

    System.out.println("Je suis exécutée !"); 

    for (Point point : points) {

        if(point.getEtat().contentEquals("erreur")) {
            Font font = new Font("Courier", Font.BOLD, 20);
            g.setFont(font);
            g.setColor(Color.red); 

        } else if(point.getEtat().contentEquals("normal")) {
            Font font = new Font("Courier", Font.BOLD, 20);
            g.setFont(font);
            g.setColor(Color.black); 

        }else if(point.getEtat().contentEquals("valide")) {
            Font font = new Font("Courier", Font.BOLD, 20);
            g.setFont(font);
            g.setColor(Color.green); 
        }

        g.drawString(point.getFichier(), point.getX(), point.getX());

    }  
  }

public void addPoint(Point point) {
    points.add(point);
}

public static void main(String[] args){
    @SuppressWarnings("unused")
    InterfaceGraphique ig = new InterfaceGraphique();

}

}

这是输出：

如果我能提供更多帮助，请告诉我。谢谢

Answer 2

我有最后一个问题，现在我想显示文件名，它在命令行中有效，但在图形界面中无效，你知道我必须添加什么吗？

import java.io.File;

导入java.io.IOException；

导入javax.swing.JFrame；

public class InterfaceGraphique 扩展 JFrame {

private static final long serialVersionUID = 1L;


 public InterfaceGraphique() {
    this.setTitle("My first Window");
    this.setSize(800,1000);
    this.setLocationRelativeTo(null);
    this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    // First Graph Object
    Graph graph = new Graph();
    String Path = "./TEST";
    try {
        parcourir2(Path);
    } catch (IOException e) {
        e.printStackTrace();
    }
    this.setContentPane(graph);

    this.setVisible(true);


}

 public static  void parcourir2 (String Path) throws IOException {

     String[] Nom = {"Point1", "Point2", "Point3","Point4","Point5","Point6","Point7","Point8","Point9","Point10"};
     Graph graph = new Graph();
        File repertoire = new File(Path);
        File[] liste = repertoire.listFiles(); 
        int y = 150;
        if (liste != null) {         
            for (int i = 0; i < liste.length; i++) {    
                if (liste[i].isDirectory()) {
                    parcourir2(liste[i].getAbsolutePath());
                }

                if(liste[i].isFile()) {
                    Point Nom[i] = new Point(liste[i].getName(),150,y,"normal");
                    graph.addPoint(Nom[i]);

                    System.out.println(liste[i] + "\n");
                    Test.TestFile.Afficher(liste[i]);
                }
                y=+50;
            }
        } else {
            System.err.println( "Nom de repertoire invalide");
        }

    }

}

Answer 3

修改了InterfaceGraphique.java

package com.java.graphics;

import java.io.File;
import java.io.IOException;

import javax.swing.JFrame;

public class InterfaceGraphique extends JFrame{

    private static final long serialVersionUID = 1L;


    public InterfaceGraphique() {
        System.out.println("Craetion");

        this.setTitle("My first Window");
        this.setSize(800, 1000);
        this.setLocationRelativeTo(null);
        this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

        // First Grapth Object
        Graph graph = new Graph();

        try {
            parcourir2("./Test", graph, new Integer(150));
        } catch (IOException e) {
            e.printStackTrace();
        }       
        this.setContentPane(graph);

        this.setVisible(true);
    }

    public static  int parcourir2 (String Path, Graph graph, Integer xValue) throws IOException {

            File repertoire = new File(Path);
            File[] liste = repertoire.listFiles(); 
            if (liste != null) {         
                for (int i = 0; i < liste.length; i++) {    
                    if (liste[i].isDirectory()) {
                        xValue = parcourir2(liste[i].getAbsolutePath(), graph, xValue);
                    }

                    if(liste[i].isFile()) {
                        Point nom = new Point(liste[i].getName(),xValue, 150,"normal");
                        graph.addPoint(nom);
                       }

                    xValue = xValue + 50;

                }
            } else {
                System.err.println( "Nom de repertoire invalide");
            }

            return xValue;

        }
}

输出：

在同一 windows java 中显示多个文本

Display many text in same windows java

java

graphics

window

draw

drawstring