如何在 java 中获取连续的周数和年份？

Question

我正在存储一些用周数引用的数据。现在，我有两个按钮来请求数据。一个用于前一周，另一个用于下一周 week.And 默认获取当前周的数据

我刚刚完成年终例外，我了解到有第 53 周明年（2020）也是如此。现在每当有第 53 周时它就会中断。（它只是跳过第 53 周）

显然，必须有更好的方法来做到这一点.. 我一直在添加异常，下面是我最终得到的代码。我是菜鸟，所以请忍受丑陋的逻辑。

LocalDate wks, mon, tue, wed, thu, fri, sat, wke;
try {
    week = Integer.parseInt(request.getParameter("week"));
    year = Integer.parseInt(request.getParameter("year"));
} catch (NumberFormatException e) {
    week = getWeek();
    year = getCurrYear();
    flag = 1;
}
LocalDate date = LocalDate.now()
.withYear(year) // year
.with(WeekFields.ISO.weekOfWeekBasedYear(), week) // week of year
.with(WeekFields.ISO.dayOfWeek(), 7);
wks = date.plusDays(-7);
if ((date + "").substring(0, 4).equals((wks + "").substring(0, 4))) {
} else if (flag == 1) {
    year++;
}
date = LocalDate.now()
.withYear(year) // year
.with(WeekFields.ISO.weekOfWeekBasedYear(), week) // week of year
.with(WeekFields.ISO.dayOfWeek(), 7);
wks = date.plusDays(-7);
mon = wks.plusDays(1);
tue = wks.plusDays(2);
wed = wks.plusDays(3);
thu = wks.plusDays(4);
fri = wks.plusDays(5);
sat = wks.plusDays(6);
wke = date;
System.out.println(week + " " + year);
heading = "<div class='row'>"
        + "<form action=\"";
if (week == 1) {
    heading += "javascript:setContent('/getData?week=52&year=" + (year - 1) + "')\" >";
} else {
    heading += "javascript:setContent('getData?week=" + (week - 1) + "&year=" + (year) + "')\" >";
}
heading += "<button type='submit'>Previous</button></form><form action=\"";
if (week == 52) {
    heading += "javascript:setContent('getData?week=1&year=" + (year + 1) + "')\" >";
} else {
    heading += "javascript:setContent('getData?week=" + (week + 1) + "&year=" + (year) + "')\" >";
}
heading += "<button type='submit'Next</button></form>";
out.print(heading);

函数：getWeek()

public static int getWeek() {
        java.util.Date date = new java.util.Date();
        SimpleDateFormat ft = new SimpleDateFormat("w");
        return (Integer.parseInt(ft.format(date)));
    }

函数：getCurrYear() {

public static int getCurrYear() {
         Date date = new Date();
         return (date.getYear() + 1900);
    }

我必须打印星期几的日期，这就是为什么星期一到星期六的变量。

I just want a function like below

function int[] getWeekYear(){
    return [prev week,prev week's year,current week,current year,next week,next week's year];
}

Answer 1

套餐java.time会给你很大的满足:

LocalDate.now().get(WeekFields.ISO.weekOfWeekBasedYear())

这将return一年中的第一个星期（现在returns 52执行），但整个包包含了你需要的一切，你只需要探索。

Answer 2

tl;博士

YearWeek
.now( 
    ZoneId.of( "Asia/Tokyo" ) 
)
.minusWeeks( 1 ) 
.getWeek()         // Returns an `int` in range of 1-52 or 1-53, the week number within a year.

详情

永远不要使用这两个 Date class 中的任何一个。它们很糟糕，现在已成为遗产。多年前，它们被 JSR 310 中定义的现代 java.time classes 所取代。

是正确的。

`YearWeek`

此外，如果您对周的定义是标准 ISO 8601 定义（周从星期一开始，第 1 周包含日历年的第一个星期四），则添加 ThreeTen-Extra library to your project. This library has classes extending the functionality of java.time. In particular, you get the YearWeek class.

获取本周。这需要一个时区。对于任何给定时刻，日期在全球各地因时区而异。

ZoneId z = ZoneId.of( "Africa/Tunis" );
YearWeek currentWeek = YearWeek.now( z ) ;

要获得前一周或下周，只需调用 plus 或 minus 方法即可。

YearWeek priorWeek = currentWeek.minusWeeks( 1 ) ;
YearWeek followingWeek = currentWeek.plusWeeks( 1 ) ;

如果您想要一周中的日期，请调用 atDay 并从 DayOfWeek 枚举中传递星期几。

LocalDate localDate = priorWeek.atDay( DayOfWeek.MONDAY ) ;

您可以查询周数及其年份（即基于周的年份）。

int weekNumber = priorWeek.getWeek() ;
int weekBasedYearNumber = priorWeek.getYear() ;

如何在 java 中获取连续的周数和年份？

How to get successive week number and year in java?

java

week-number

tl;博士

详情

`YearWeek`