我如何在 Django 中正确使用 slug url？

Question

你好，我是 Django 的新手，我正在尝试建立一个网站。 在管理页面 http://127.0.0.1:8000/admin/posts/post/ 我添加了两个帖子，发现一个有鼻涕虫，**第一个鼻涕虫是第一个，第二个是第二个问题是当我尝试到达 http://127.0.0.1:8000/posts/first or http://127.0.0.1:8000/posts/second 它给了我一个 404 错误并且它告诉我**

Using the URLconf defined in custom.urls, Django tried these URL patterns, in this order:
admin/
posts/ [name='posts_list']
<slug>
The current path, posts/first, didn't match any of these.

这是models.py

from django.db import models
from django.conf import settings
Create your models here.

User = settings.AUTH_USER_MODEL

class Author(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE)
    email = models.EmailField()
    phone_num = models.IntegerField(("Phone number"))

    def __str__(self):
       return self.user.username

class Post(models.Model):
    title = models.CharField(max_length=120)
    description = models.TextField()
    slug = models.SlugField()
    image = models.ImageField()
    author = models.OneToOneField(Author, on_delete=models.CASCADE)


    def __str__(self):
        return self.title

这是views.py

from django.shortcuts import render, get_object_or_404
from .models import Post
# Create your views here.


def posts_list(request):
    all_posts = Post.objects.all()
    return render(request, 
                  "posts/posts_list.html", 
                  context = {"all_posts": all_posts})


def posts_detail(request, slug):
    unique_slug = get_object_or_404(Post, slug = slug)

    return render(request, "posts/posts_detail.html", {"post": unique_slug})

这是urls.py

from django.contrib import admin
from django.urls import path
from posts.views import posts_list, posts_detail
urlpatterns = [
        path('admin/', admin.site.urls),
        path("posts/", posts_list, name = "posts_list"),
        path("<slug>", posts_detail), #, name = "unique_slug"
    ]

这是模板： posts_list.html

<!DOCTYPE html>
<html>
    <head>
        <title>
        </title>
    </head>
    <body>
        {{ all_posts }}
    </body>
</html>

post_detail.html

<!DOCTYPE html>
<html>
    <head>
        <title>
        </title>
    </head>
    <body>
        {{ post }}
    </body>
</html>

Answer 1

A slug 从不包含斜杠。看起来您的 url 带有 posts/ 前缀。所以你可以改变你的urls.py：

from django.contrib import admin
from django.urls import path
from posts.views import posts_list, posts_detail

urlpatterns = [
    path('admin/', admin.site.urls),
    path('posts/', posts_list, name='posts_list'),
    path(<b>'posts/<slug:slug>/'</b>, posts_detail, name='unique_slug'),
]

最好添加路径转换器的类型，所以 <<b>slug:</b>slug>.

您可能希望使用 django-autoslug [GitHub] 来根据特定字段自动构建 slug。

Answer 2

你这里先犯了两个错误>>>

#你还没有用逗号关闭最后一个括号

path("<slug>", posts_detail), #, name = "unique_slug"__<<

你犯的第二个错误是你没有定义 slug 类型，这一点很重要

我如何在 Django 中正确使用 slug url？

How do i use slug urls correctly in Django?

html

python

django

url

slug