在自定义类型中使用迭代器属性
Use a interator propeties in a cunston type
我正在编写 Go 代码,其中我使用基础映射 [string] int 创建了一个类型,我需要创建一个 return 映射的方法,反转键和值。我开始编写代码,但我无法迭代我创建的类型。
到目前为止,我已经编写了以下代码:
package constants
type Month map[string]int;
// LongMonth is a relationship with string and date value (int)
var LongMonth = Month{
"Janary":1,
"February":2,
"March":3,
"April":4,
"May":5,
"June": 6,
"July": 7,
"August": 8,
"September": 9,
"Octuber": 10,
"Novenber": 11,
"Decenber": 12,
}
// ShortMonth is a relationship with a resume string and date value (int)
var ShortMonth = Month{
"Jan":1,
"Feb":2,
"Mar":3,
"Apr":4,
"May":5,
"Jun": 6,
"Jul": 7,
"Aug": 8,
"Sep": 9,
"Oct": 10,
"Nov": 11,
"Dec": 12,
}
func (m* Month) Reverse() map[int]string {
n:=make(map[int]string);
for k, v := range m {
n[v] = k
}
return n
};
// LongMonthReverse is a relationship with string and date value (int)
// var LongMonthReverse = reverseMonth(LongMonth);
// ShortMonthReverse is a relationship with string and date value (int)
// var ShortMonthReverse = reverseMonth(ShortMonth);
我需要 Reverse 功能 return 反转月份。例如:月 = {"Jan": 1..."Dec": 12} 和 month.Reverse() returns {1: "Jan"...12 : "Dec"}
您不能遍历指针,要么将 func (m* Month) Reverse() map[int]string
的方法接口更改为 func (m Month) Reverse() map[int]string
,要么您需要在 Reverse()
[=15] 中使用 *m
=]
package main
import "fmt"
type Month map[string]int
// LongMonth is a relationship with string and date value (int)
var LongMonth = Month{
"Janary":1,
"February":2,
"March":3,
"April":4,
"May":5,
"June": 6,
"July": 7,
"August": 8,
"September": 9,
"Octuber": 10,
"Novenber": 11,
"Decenber": 12,
}
// ShortMonth is a relationship with a resume string and date value (int)
var ShortMonth = Month{
"Jan":1,
"Feb":2,
"Mar":3,
"Apr":4,
"May":5,
"Jun": 6,
"Jul": 7,
"Aug": 8,
"Sep": 9,
"Oct": 10,
"Nov": 11,
"Dec": 12,
}
func (m* Month) Reverse() map[int]string {
n:=make(map[int]string)
// this is the fix
for k, v := range *m {
n[v] = k
}
return n
}
func main() {
fmt.Println(ShortMonth.Reverse())
}
我正在编写 Go 代码,其中我使用基础映射 [string] int 创建了一个类型,我需要创建一个 return 映射的方法,反转键和值。我开始编写代码,但我无法迭代我创建的类型。
到目前为止,我已经编写了以下代码:
package constants
type Month map[string]int;
// LongMonth is a relationship with string and date value (int)
var LongMonth = Month{
"Janary":1,
"February":2,
"March":3,
"April":4,
"May":5,
"June": 6,
"July": 7,
"August": 8,
"September": 9,
"Octuber": 10,
"Novenber": 11,
"Decenber": 12,
}
// ShortMonth is a relationship with a resume string and date value (int)
var ShortMonth = Month{
"Jan":1,
"Feb":2,
"Mar":3,
"Apr":4,
"May":5,
"Jun": 6,
"Jul": 7,
"Aug": 8,
"Sep": 9,
"Oct": 10,
"Nov": 11,
"Dec": 12,
}
func (m* Month) Reverse() map[int]string {
n:=make(map[int]string);
for k, v := range m {
n[v] = k
}
return n
};
// LongMonthReverse is a relationship with string and date value (int)
// var LongMonthReverse = reverseMonth(LongMonth);
// ShortMonthReverse is a relationship with string and date value (int)
// var ShortMonthReverse = reverseMonth(ShortMonth);
我需要 Reverse 功能 return 反转月份。例如:月 = {"Jan": 1..."Dec": 12} 和 month.Reverse() returns {1: "Jan"...12 : "Dec"}
您不能遍历指针,要么将 func (m* Month) Reverse() map[int]string
的方法接口更改为 func (m Month) Reverse() map[int]string
,要么您需要在 Reverse()
[=15] 中使用 *m
=]
package main
import "fmt"
type Month map[string]int
// LongMonth is a relationship with string and date value (int)
var LongMonth = Month{
"Janary":1,
"February":2,
"March":3,
"April":4,
"May":5,
"June": 6,
"July": 7,
"August": 8,
"September": 9,
"Octuber": 10,
"Novenber": 11,
"Decenber": 12,
}
// ShortMonth is a relationship with a resume string and date value (int)
var ShortMonth = Month{
"Jan":1,
"Feb":2,
"Mar":3,
"Apr":4,
"May":5,
"Jun": 6,
"Jul": 7,
"Aug": 8,
"Sep": 9,
"Oct": 10,
"Nov": 11,
"Dec": 12,
}
func (m* Month) Reverse() map[int]string {
n:=make(map[int]string)
// this is the fix
for k, v := range *m {
n[v] = k
}
return n
}
func main() {
fmt.Println(ShortMonth.Reverse())
}