如何将按 ID 过滤添加到我的用户解析器？

Question

我有 schema.py 是这样的：

import graphene
from app import db
from graphene import relay
from app.models import User as UserModel, Event as EventModel
from graphene_sqlalchemy import SQLAlchemyConnectionField, SQLAlchemyObjectType


class User(SQLAlchemyObjectType):
    class Meta:
        model = UserModel
        interfaces = (relay.Node, )


class UserConnection(relay.Connection):
    class Meta:
        node = User


class Event(SQLAlchemyObjectType):
    class Meta:
        model = EventModel
        interfaces = (relay.Node, )


class EventConnections(relay.Connection):
    class Meta:
        node = Event


class CreateUser(graphene.Mutation):
    class Arguments:
        username = graphene.String(required=True)
        fname = graphene.String(required=True)
        surname = graphene.String(required=True)
        email = graphene.String(required=True)
        password = graphene.String(required=True)

    user = graphene.Field(lambda: User)

    def mutate(self, info, username, fname, surname, email, password):
        user = UserModel.query.filter_by(username=username).first()

        if user is None:
            user = UserModel(username=username, fname=fname, surname=surname, email=email, password=password)
        else:
            return None
        db.session.add(user)
        db.session.commit()

        return CreateUser(user=user)


class Query(graphene.ObjectType):
    node = relay.Node.Field()

    # queries that return individual models
    user = graphene.Field(lambda: User, username=graphene.String())

    event = graphene.Field(lambda: Event, title=graphene.String())

    # queries that return all models of given type
    all_users = SQLAlchemyConnectionField(UserConnection)

    all_events = SQLAlchemyConnectionField(EventConnections)

    # resolvers
    def resolve_user(self, info, **kwargs):
        query = User.get_query(info)
        # id = kwargs.get("id")
        username = kwargs.get('username')
        return query.filter(UserModel.username == username).first()

    def resolve_event(self, info, **kwargs):
        query = Event.get_query(info)
        # id = kwargs.get("id")
        title = kwargs.get('title')
        return query.filter(EventModel.title == title).first()


class Mutation(graphene.ObjectType):
    create_user = CreateUser.Field()


schema = graphene.Schema(query=Query, mutation=Mutation, types=[User, Event])

我的模型是这样的：

from app import db
from datetime import datetime


class User(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    username = db.Column(db.String(30), unique=True, nullable=False)
    fname = db.Column(db.String(20), nullable=False)
    surname = db.Column(db.String(35), nullable=False)
    is_verified = db.Column(db.Boolean(), default=False)
    profile_pic = db.Column(db.Text(), default="default.jpg")
    email = db.Column(db.String(120), nullable=False)
    password = db.Column(db.String(50), nullable=False)
    events = db.relationship("Event", backref="organizer", lazy=True)

    def __repr__(self):
        print(f"User({self.id}, {self.name}, {self.surname}, {self.email}")


class Event(db.Model):
    id = db.Column(db.Integer, primary_key=True)
    title = db.Column(db.String(120), nullable=False)
    date_posted = db.Column(db.String(50), nullable=False, default=datetime.now().isoformat())
    description = db.Column(db.Text)
    user_id = db.Column(db.Integer, db.ForeignKey("user.id"), nullable=False)

所以如果我想获得所有用户，我输入：

query{
  allUsers{
    edges{
      node{
        id
        username
        email
      }
    }
  }
}

当我得到 id 时，我得到类似 "id": "VXNlcjoy" 的东西，但在我的模型中 id 是一个 int。如果我确实更改我的解析器以按前面提到的 id 进行过滤，sqlalchemy 会抛出一个错误，因为数据库中的 id 是整数。然后我更改解析器以接受 id 作为整数，并按真实 id 进行过滤。更改后使用解析器进行过滤但会发生这种情况：

{
  user(id: 1){
    id

  }
}

回复：

{
  "data": {
    "user": {
      "id": "VXNlcjoy"
    }
  }
}

我想了一下，我认为有两种方法：
- 让 graphql return 返回数据库中的整数 ID
- 以某种方式让解析器通过 graphql 给出的字符串 id 查询用户和事件 ("VXNlcjoy")

我怎样才能做到这一点？

Answer 1

我找到了，我覆盖了名为 id 的 graphql 保留变量，该变量用于缓存和分页。在 models.py 中，我将列 id 重命名为 uuid，在 table 事件中

user_id = db.Column(db.Integer, db.ForeignKey("user.id"), nullable=False)

至

user_uuid = db.Column(db.Integer, db.ForeignKey("user.uuid"), nullable=False)

得到这个：

mutation{
  createUser(email:"saki1@saki.com", fname:"saki",surname:"sakal",username:"saki709", password:"sakisaki"){
    user{
      uuid
      id
    }
  }
}

回复：

{
  "data": {
    "createUser": {
      "user": {
        "uuid": "1",
        "id": "VXNlcjox"
      }
    }
  }
}

TL;DR - 将 id 重命名为 uuid 因为 graphql 有它自己的变量 id

如何将按 ID 过滤添加到我的用户解析器？

How to add filtering by id to my user resolver?

python

flask

graphql

flask-graphql

graphene-sqlalchemy