需要 Lat 形式的 Path,long 使用 pgrouting
Need Path in the form of Lat,long using pgrouting
我正在使用此查询查找使用 postgresql、postgis、pgrouting 的路径,postgis_topology 使用 nodejs
client.query(
"WITH dijkstra AS (
SELECT *
FROM pgr_dijkstra('SELECT id,source,target,distance AS cost
FROM edges_noded',230965,3338,false))
SELECT seq,
CASE WHEN dijkstra.node = edges_noded.source THEN edges_noded.the_geom
ELSE ST_Reverse(edges_noded.the_geom) END AS route_geom
FROM dijkstra JOIN edges_noded ON(edge = id)
ORDER BY seq",(err,res)=>{ var data = res.rows;})
现在的问题是这个查询 returns 两列是
我认为上图中的 route_geom 列有路径信息。
如何修改上述查询以获取经纬度形式的路径。
我需要经纬度形式的完整路径。
如果我没理解错的话,您只需将现有的坐标转换为您的应用程序可以读取的格式。您可以直接从 PostGIS 获得许多格式。以下是您可能感兴趣的一些内容:
数据样本
CREATE TEMPORARY TABLE t (seq INT, the_geom GEOMETRY);
INSERT INTO t VALUES (1,'POINT(1 2)'),(2,'POINT(2 3)');
PostGIS 几何格式的几何图形 - 正如您目前所做的那样。
SELECT seq, the_geom FROM t;
seq | the_geom
-----+--------------------------------------------
1 | 0101000000000000000000F03F0000000000000040
2 | 010100000000000000000000400000000000000840
(2 Zeilen)
SELECT seq, ST_X(the_geom), ST_Y(the_geom) FROM t;
seq | st_x | st_y
-----+------+------
1 | 1 | 2
2 | 2 | 3
(2 Zeilen)
作为 WKT - ST_AsText
SELECT seq, ST_AsText(the_geom) FROM t;
seq | st_astext
-----+------------
1 | POINT(1 2)
2 | POINT(2 3)
(2 Zeilen)
.. 或 GeoJSON - ST_AsGeoJSON
SELECT seq, ST_AsGeoJSON(the_geom) FROM t;
seq | st_asgeojson
-----+--------------------------------------
1 | {"type":"Point","coordinates":[1,2]}
2 | {"type":"Point","coordinates":[2,3]}
(2 Zeilen)
所以你的CTE
很可能看起来像这样
WITH dijkstra AS (
SELECT *
FROM pgr_dijkstra('SELECT id,source,target,distance AS cost
FROM edges_noded',230965,3338,false))
SELECT seq,
CASE WHEN dijkstra.node = edges_noded.source THEN ST_X(edges_noded.the_geom)
ELSE ST_X(ST_Reverse(edges_noded.the_geom)) END AS route_geom_x,
CASE WHEN dijkstra.node = edges_noded.source THEN ST_Y(edges_noded.the_geom)
ELSE ST_Y(ST_Reverse(edges_noded.the_geom)) END AS route_geom_y
FROM dijkstra JOIN edges_noded ON(edge = id)
ORDER BY seq
我正在使用此查询查找使用 postgresql、postgis、pgrouting 的路径,postgis_topology 使用 nodejs
client.query(
"WITH dijkstra AS (
SELECT *
FROM pgr_dijkstra('SELECT id,source,target,distance AS cost
FROM edges_noded',230965,3338,false))
SELECT seq,
CASE WHEN dijkstra.node = edges_noded.source THEN edges_noded.the_geom
ELSE ST_Reverse(edges_noded.the_geom) END AS route_geom
FROM dijkstra JOIN edges_noded ON(edge = id)
ORDER BY seq",(err,res)=>{ var data = res.rows;})
现在的问题是这个查询 returns 两列是
我认为上图中的 route_geom 列有路径信息。
如何修改上述查询以获取经纬度形式的路径。
我需要经纬度形式的完整路径。
如果我没理解错的话,您只需将现有的坐标转换为您的应用程序可以读取的格式。您可以直接从 PostGIS 获得许多格式。以下是您可能感兴趣的一些内容:
数据样本
CREATE TEMPORARY TABLE t (seq INT, the_geom GEOMETRY);
INSERT INTO t VALUES (1,'POINT(1 2)'),(2,'POINT(2 3)');
PostGIS 几何格式的几何图形 - 正如您目前所做的那样。
SELECT seq, the_geom FROM t;
seq | the_geom
-----+--------------------------------------------
1 | 0101000000000000000000F03F0000000000000040
2 | 010100000000000000000000400000000000000840
(2 Zeilen)
SELECT seq, ST_X(the_geom), ST_Y(the_geom) FROM t;
seq | st_x | st_y
-----+------+------
1 | 1 | 2
2 | 2 | 3
(2 Zeilen)
作为 WKT - ST_AsText
SELECT seq, ST_AsText(the_geom) FROM t;
seq | st_astext
-----+------------
1 | POINT(1 2)
2 | POINT(2 3)
(2 Zeilen)
.. 或 GeoJSON - ST_AsGeoJSON
SELECT seq, ST_AsGeoJSON(the_geom) FROM t;
seq | st_asgeojson
-----+--------------------------------------
1 | {"type":"Point","coordinates":[1,2]}
2 | {"type":"Point","coordinates":[2,3]}
(2 Zeilen)
所以你的CTE
很可能看起来像这样
WITH dijkstra AS (
SELECT *
FROM pgr_dijkstra('SELECT id,source,target,distance AS cost
FROM edges_noded',230965,3338,false))
SELECT seq,
CASE WHEN dijkstra.node = edges_noded.source THEN ST_X(edges_noded.the_geom)
ELSE ST_X(ST_Reverse(edges_noded.the_geom)) END AS route_geom_x,
CASE WHEN dijkstra.node = edges_noded.source THEN ST_Y(edges_noded.the_geom)
ELSE ST_Y(ST_Reverse(edges_noded.the_geom)) END AS route_geom_y
FROM dijkstra JOIN edges_noded ON(edge = id)
ORDER BY seq