如何解决函数 datediff（未知，没有时区的时间戳，没有时区的时间戳）不存在

Question

SELECT "reviewedAt", "createdAt", DATEDIFF('hour', "createdAt"::timestamp, "reviewedAt"::timestamp) as hours_approved from "yadda$prod"."Application"

error [42883] ERROR: function datediff(unknown, timestamp without time zone, timestamp without time zone) does not exist 提示：没有函数匹配给定的名称和参数类型。您可能需要添加显式类型转换。排名：36

Answer 1

试试这个：

SELECT 
"reviewedAt",
"createdAt",
DATE_PART('day', "reviewedAt"::timestamp - "createdAt"::timestamp) * 24 + DATE_PART('hour', "reviewedAt"::timestamp - "createdAt"::timestamp) AS hours_approved 
FROM "yadda$prod"."Application"

Answer 2

还有一个解决方案：

SELECT 
    "reviewedAt",
    "createdAt",
    (EXTRACT(EPOCH FROM "reviewedAt"::timestamp - "createdAt"::timestamp)/3600)::int2 AS hours_approved
FROM "yadda$prod"."Application";

如何解决函数 datediff（未知，没有时区的时间戳，没有时区的时间戳）不存在

how to resolve function datediff(unknown, timestamp without time zone, timestamp without time zone) does not exist

postgresql

datediff