检查 Alfresco Endpoint URL 在 Java 中是否可用

Question

您好，我创建了一个 Lambda 函数，并尝试检查我的端点之一 URL（Alfresco 进程）是否可用，同时检查 URL 可用性代码完美适用于 http URL 不适用于 HTTP。

我的要求是，如果在检查可用性时端点 URL 不可用，我必须使用 SES 发送邮件我收到 Https URL 的

错误消息

错误：java.net.ConnectException：连接refused:connect

这是我的示例代码


package com.Firstlambda;

import com.amazonaws.auth.AWSStaticCredentialsProvider;
import com.amazonaws.auth.BasicAWSCredentials;
import com.amazonaws.regions.Regions;
import com.amazonaws.services.simpleemail.AmazonSimpleEmailService;
import com.amazonaws.services.simpleemail.AmazonSimpleEmailServiceClientBuilder;
import com.amazonaws.services.simpleemail.model.*;

import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.URL;

public class test {
    public static void main(String[] args) throws IOException {

        BasicAWSCredentials creds = new BasicAWSCredentials("xxxxxxx",
                "xxxxxxxx");

        final String FROM = "xxxxxx";
        final String TO = "xxxxxx";
//        final String CONFIGSET = "xxxxx";
        final String SUBJECT = "Amazon SES test (AWS SDK for Java)";


        final String HTMLBODY = "<h1>Amazon SES test (AWS SDK for Java)</h1>"
                + "<p>This email was sent with <a href='https://aws.amazon.com/ses/'>"
                + "Amazon SES</a> using the <a href='https://aws.amazon.com/sdk-for-java/'>"
                + "AWS SDK for Java</a>";


        final String TEXTBODY = "This email was sent through Amazon SES "
                + "using the AWS SDK for Java.";

        //String GetStaus = getStatus("https://www.youtube.com");
        String GetStaus = getStatus("http://localhost:9020/OCR/test");

        if (GetStaus.toLowerCase().equals("green")) {
            AmazonSimpleEmailService client =
                    AmazonSimpleEmailServiceClientBuilder.standard()
                            .withCredentials(new AWSStaticCredentialsProvider(creds))
                            .withRegion(Regions.US_EAST_1).build();

            SendEmailRequest request = new SendEmailRequest()
                    .withDestination(
                            new Destination().withToAddresses(TO))
                    .withMessage(new Message()
                            .withBody(new Body()
                                    .withHtml(new Content()
                                            .withCharset("UTF-8").withData(HTMLBODY))
                                    .withText(new Content()
                                            .withCharset("UTF-8").withData(TEXTBODY)))
                            .withSubject(new Content()
                                    .withCharset("UTF-8").withData(SUBJECT)))
                    .withSource(FROM);
            client.sendEmail(request);
        }
        System.out.println("Email sent!");
    }


    public static String getStatus(String url) throws IOException {

        String result = "";
        try {
            URL siteURL = new URL(url);
            HttpURLConnection connection = (HttpURLConnection) siteURL
                    .openConnection();
            connection.setRequestMethod("GET");
            connection.connect();

            int code = connection.getResponseCode();
            if (code == 200) {
                result = "Green";
            }
        } catch (Exception e) {
            result = "->Red<-";
        }
        return result;
    }
}

任何人都可以帮助我如何在我的 Spring 启动 java 应用程序中检查 http URL 的可用性吗？如果解决了，我也必须在我的 java 服务中使用相同的方法。提前致谢

根据要求，我已经放置了整个 stackrace

java.net.ConnectException: Connection refused: connect
    at java.base/java.net.PlainSocketImpl.connect0(Native Method)
    at java.base/java.net.PlainSocketImpl.socketConnect(PlainSocketImpl.java:101)
    at java.base/java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:399)
    at java.base/java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:242)
    at java.base/java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:224)
    at java.base/java.net.SocksSocketImpl.connect(SocksSocketImpl.java:403)
    at java.base/java.net.Socket.connect(Socket.java:591)
    at java.base/sun.security.ssl.SSLSocketImpl.connect(SSLSocketImpl.java:285)
    at java.base/sun.security.ssl.BaseSSLSocketImpl.connect(BaseSSLSocketImpl.java:173)
    at java.base/sun.net.NetworkClient.doConnect(NetworkClient.java:182)
    at java.base/sun.net.www.http.HttpClient.openServer(HttpClient.java:474)
    at java.base/sun.net.www.http.HttpClient.openServer(HttpClient.java:569)
    at java.base/sun.net.www.protocol.https.HttpsClient.<init>(HttpsClient.java:265)
    at java.base/sun.net.www.protocol.https.HttpsClient.New(HttpsClient.java:372)
    at java.base/sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.getNewHttpClient(AbstractDelegateHttpsURLConnection.java:191)
    at java.base/sun.net.www.protocol.http.HttpURLConnection.plainConnect0(HttpURLConnection.java:1181)
    at java.base/sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:1075)
    at java.base/sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.connect(AbstractDelegateHttpsURLConnection.java:177)
    at java.base/sun.net.www.protocol.https.HttpsURLConnectionImpl.connect(HttpsURLConnectionImpl.java:163)
    at com.Firstlambda.test.getStatus(test.java:70)
    at com.Firstlambda.test.main(test.java:35)

Answer 1

以上代码运行良好。这是我组织的代理问题。如果有人遇到同样的问题，请联系您组织的管理团队，检查是否存在任何防火墙问题

检查 Alfresco Endpoint URL 在 Java 中是否可用

Check the Alfresco Endpoint URL is available or not in Java

java

spring-boot

aws-sdk

aws-lambda

alfresco-maven