return外键存在信息如何变为select结果?
How return foregin key existence information to select result?
我有一个问题:
SELECT `Name`, `ID_dir`, 999 as `children`
FROM `dir` dir WHERE dir.`fid_parent` IS NULL
AND (
EXISTS (
SELECT 1
FROM `file` f
WHERE dir.ID_dir = f.fid_parent
)
OR (
SELECT 1
FROM `dir` d2
WHERE dir.ID_dir = d2.fid_parent
)
)
我在哪里检查目录是否有任何外键。
我如何移动该信息来代替 "Select ... 999 as children
" 中的 999?
我想 return (0 or 1) xor Boolean in that place as children
.
将 EXISTS
子查询放入 SELECT
列表。
SELECT Name, ID_Dir, (
EXISTS (
SELECT 1
FROM `file` f
WHERE dir.ID_dir = f.fid_parent
)
OR (
SELECT 1
FROM `dir` d2
WHERE dir.ID_dir = d2.fid_parent
)
) AS children
FROM dir WHERE fid_parent IS NULL
我有一个问题:
SELECT `Name`, `ID_dir`, 999 as `children`
FROM `dir` dir WHERE dir.`fid_parent` IS NULL
AND (
EXISTS (
SELECT 1
FROM `file` f
WHERE dir.ID_dir = f.fid_parent
)
OR (
SELECT 1
FROM `dir` d2
WHERE dir.ID_dir = d2.fid_parent
)
)
我在哪里检查目录是否有任何外键。
我如何移动该信息来代替 "Select ... 999 as children
" 中的 999?
我想 return (0 or 1) xor Boolean in that place as children
.
将 EXISTS
子查询放入 SELECT
列表。
SELECT Name, ID_Dir, (
EXISTS (
SELECT 1
FROM `file` f
WHERE dir.ID_dir = f.fid_parent
)
OR (
SELECT 1
FROM `dir` d2
WHERE dir.ID_dir = d2.fid_parent
)
) AS children
FROM dir WHERE fid_parent IS NULL