如果我复制并粘贴它，为什么 console.log() 什么都没有？

Question

我在 Glitch 上有这段代码运行可以在对话前添加 \n ，如果我在 space 中输入一些东西，其中单词在 toFormat 中，它可以正常工作，但如果我复制并粘贴一些东西进去，它没有 console.log 任何东西

/* !!! */
let toformat = `
“Excuse me,” he said. The young woman didn’t respond. “What are you doing?” “Hey, I’m talking to you” Rudy said.
`
/* !!! */

let truef = false

/* !!! */
let run = true

/* !!! */

if(run){

  let res = []

  let dialogue = []
  let other = []
  let split = toformat.split('"').join('|"').split('|').slice(1)

  split.forEach((x, i) => {
    if(i % 2 == 1){
      other.push(x)
    } else {
      dialogue.push(x)
    }
  })



  for(let i = 0; i < dialogue.length; i++){
    res.push('\n' + dialogue[i] + '"')
    res.push(other[i].slice(1))
  }

  console.log(res.join(''))
  console.log(Math.random())

}

Answer 1

问题是您试图在 " 上拆分，但字符串包含 “，这是一个不同的 ASCII 字符。常见的复制+粘贴问题。

更改格式中的字符有效：

/* !!! */
let toformat = `
"Excuse me," he said. The young woman didn't respond. "What are you doing?" "Hey, I’m talking to you" Rudy said.
`
/* !!! */

let truef = false

/* !!! */
let run = true

/* !!! */

if(run){

  let res = []

  let dialogue = []
  let other = []
  let split = toformat.split('"').join('|"').split('|').slice(1)

  split.forEach((x, i) => {
    if(i % 2 == 1){
      other.push(x)
    } else {
      dialogue.push(x)
    }
  })



  for(let i = 0; i < dialogue.length; i++){
    res.push('\n' + dialogue[i] + '"')
    res.push(other[i].slice(1))
  }

  console.log(res.join(''))
  console.log(Math.random())

}

结果：

"Excuse me," he said. The young woman didn't respond. 
"What are you doing?" 
"Hey, I’m talking to you" Rudy said.

如果我复制并粘贴它，为什么 console.log() 什么都没有？

Why doesn't it console.log() anything if I copy and paste it?

javascript

console.log