如何使用 openFileChooser 打开文本文件
How to open a text file using openFileChooser
我正在尝试通过菜单按钮打开文件,但找不到合适的方法来使用动作侦听器执行此操作。我需要对此代码添加哪些内容才能执行此操作?
private void jMenuItem1ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
int returnValue = openFileChooser.showOpenDialog(this);
if (returnValue == JFileChooser.APPROVE_OPTION){
JOptionPane.showMessageDialog(null, "This a vaild file",
"Display Message",
JOptionPane.INFORMATION_MESSAGE);
}
else {
JOptionPane.showMessageDialog(null, "No file was selected",
"Display Message",
JOptionPane.INFORMATION_MESSAGE);
}
}
假设您已经知道如何创建 UI。所以首先你需要定义一个 JFileChooser 对象:
//Create a file chooser as final
final JFileChooser fc = new JFileChooser();
在你的事件方法中只需要处理动作:
public void actionPerformed(ActionEvent e) {
//Handle open button action.
if (e.getSource() == openButton) {
int returnVal = fc.showOpenDialog(YourClassName.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//What to do with the file here.
} else {
}
}
}
请参阅此 link 了解更多详细信息:OracleFileChooserDocument
我能够完成这项工作,下面的代码将允许您从文件选择器中 select 一个文件,然后显示该文件。
private void jMenuItem1ActionPerformed(java.awt.event.ActionEvent evt) {
JFileChooser fileChooser = new JFileChooser();
fileChooser.setCurrentDirectory(new File(System.getProperty("user.home")));
int result = fileChooser.showOpenDialog(this);
if (result == JFileChooser.APPROVE_OPTION) {
File selectedFile = fileChooser.getSelectedFile();
System.out.println("Selected file: " + selectedFile.getAbsolutePath());
try {
Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + selectedFile.getAbsolutePath());
} catch (Exception e) {
JOptionPane.showMessageDialog(null, "Error");
}
}
}
我正在尝试通过菜单按钮打开文件,但找不到合适的方法来使用动作侦听器执行此操作。我需要对此代码添加哪些内容才能执行此操作?
private void jMenuItem1ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
int returnValue = openFileChooser.showOpenDialog(this);
if (returnValue == JFileChooser.APPROVE_OPTION){
JOptionPane.showMessageDialog(null, "This a vaild file",
"Display Message",
JOptionPane.INFORMATION_MESSAGE);
}
else {
JOptionPane.showMessageDialog(null, "No file was selected",
"Display Message",
JOptionPane.INFORMATION_MESSAGE);
}
}
假设您已经知道如何创建 UI。所以首先你需要定义一个 JFileChooser 对象:
//Create a file chooser as final
final JFileChooser fc = new JFileChooser();
在你的事件方法中只需要处理动作:
public void actionPerformed(ActionEvent e) {
//Handle open button action.
if (e.getSource() == openButton) {
int returnVal = fc.showOpenDialog(YourClassName.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//What to do with the file here.
} else {
}
}
}
请参阅此 link 了解更多详细信息:OracleFileChooserDocument
我能够完成这项工作,下面的代码将允许您从文件选择器中 select 一个文件,然后显示该文件。
private void jMenuItem1ActionPerformed(java.awt.event.ActionEvent evt) {
JFileChooser fileChooser = new JFileChooser();
fileChooser.setCurrentDirectory(new File(System.getProperty("user.home")));
int result = fileChooser.showOpenDialog(this);
if (result == JFileChooser.APPROVE_OPTION) {
File selectedFile = fileChooser.getSelectedFile();
System.out.println("Selected file: " + selectedFile.getAbsolutePath());
try {
Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + selectedFile.getAbsolutePath());
} catch (Exception e) {
JOptionPane.showMessageDialog(null, "Error");
}
}
}