我如何能够显示用户输入数组中的最大和最小数字？

Question

有人能帮我看看我的代码有什么问题吗？我在显示数组中最大和最小的部分时遇到了问题。抱歉，我是 java 的新手。非常感谢

package problem6;
import java.util.Scanner;
public class Problem6 {

    public static void main(String[] args) {
   int input;
   int min = 0;
   int max = 0;
    Scanner keyboard = new Scanner(System.in);   
    System.out.println("How many numbers do you want to enter?");
    input = keyboard.nextInt();

    int array[] = new int[input]; 

        for (int i = 0 ; i < array.length; i++ ) {
           System.out.println("Enter number: ");
           array[i] = keyboard.nextInt(); 
        }  

        {   
            if (input > max)   
            {   
                max = input;  
            } 
            else if (input <= min)   
            {   
                min = input;   
            }     
        }   
        System.out.print("\nLargest: " + max);   
        System.out.print("\nSmallest:" + min); 
    }   
}

Answer 1

Post 您读取了值，您需要遍历数组并尝试使用您的 mix/max 比较逻辑，例如：

int min = Integer.MAX_VALUE;//change your assignment of 0 as numbers can be negative
int max = Integer.MIN_VALUE;    
for (int number : array) {//use separate for loop or use the same for loop to which you add numbers in array.
    if (number > max) {   
        max = input;  
    } 
    else if (number < min) {   
       min = input;   
    }     
}

使用相同的 for 循环：

int min = Integer.MAX_VALUE;//change your assignment of 0 as numbers can be negative
int max = Integer.MIN_VALUE; 
for (int i = 0 ; i < array.length; i++ ) {
    System.out.println("Enter number: ");
    array[i] = keyboard.nextInt(); 
    if (array[i] > max) {   
        max = array[i];  
    } 
    else if (array[i] < min)   
    {   
       min = array[i];   
    }     
}

Answer 2

您需要有此代码：

int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;
    for (int i = 0 ; i < array.length; i++ ) {
                if (array[i]> max)   
                {   
                    max = array[i];  
                } 
                else if (array[i] <= min)   
                {   
                    min = array[i];   
                }     
            }   
            System.out.print("\nLargest: " + max);   
            System.out.print("\nSmallest:" + min);

Answer 3

错误是

一对额外的大括号，以及 2. 将输入大小而不是数组元素与最小值和最大值进行比较。

可能的工作代码如下所示：-

package problem6;
import java.util.Scanner;
public class Problem6 {

    public static void main(String[] args) {
   int input;
   int min = 0;
   int max = 0;
    Scanner keyboard = new Scanner(System.in);   
    System.out.println("How many numbers do you want to enter?");
    input = keyboard.nextInt();

    int array[] = new int[input]; 

        for (int i = 0 ; i < array.length; i++ ) {
           System.out.println("Enter number: ");
           array[i] = keyboard.nextInt();

            if (array[i] >= max)   
            {   
                max = array[i];  
            } 
            else if (array[i] <= min)   
            {   
                min = array[i];   
            }     
        }   
        System.out.print("\nLargest: " + max);   
        System.out.print("\nSmallest:" + min); 
    }   
}

Answer 4

你甚至可以试试这个。

int max=array[0], min=array[0];

for(int x=0; x<array.length; x++){
    max = array[x]>max?array[x]:max;        
    min = array[x]<min?array[x]:min;
}

首先将第一个数组元素设置为最小值和最大值。

我如何能够显示用户输入数组中的最大和最小数字？

How am I able to display the largest and the smallest number from the array of the user's input?

java

arrays