使用 XML 从 Element 获取值

Question

我可以从 XML 中获取 header 属性，但我想提取标题，该标题向下几个节点。我在代码中留下了我最近的尝试。 FirstAttributes 工作所以我知道我正在连接，如果我 return Console.WriteLine(e) 我得到完整的 XML。

var url = "http://musicbrainz.org/ws/2/release-group/?query=artist:%22coldplay%22%20AND%20primarytype:%22single%22";

HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
request.UserAgent = "Hello World Super Script";
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
XDocument doc = XDocument.Load(response.GetResponseStream());

IEnumerable<XElement> childList =
from el in doc.Elements()  
select el; 
//title is element we need  
foreach (XElement e in childList)  
Console.WriteLine("{0} {1} {2}", e.FirstAttribute, e.FirstAttribute.NextAttribute, e.Element("release-group").Attribute("title"));

研究：C# extracting data from XML

Answer 1

您可以执行以下操作。

var doc = XDocument.Load(response.GetResponseStream());
XNamespace ns = "http://musicbrainz.org/ns/mmd-2.0#";

var titleList = doc.Descendants(ns + "title");
foreach (var element in titleList) 
    Console.WriteLine(element.Value);

XDocument.Descendants() 允许您搜索具有指定名称的子节点。请注意，您需要指定名称空间和元素名称。

如果您观察来自 WebRequest 的响应，您可以找到命名空间的详细信息。

xmlns="http://musicbrainz.org/ns/mmd-2.0#"

Sample Demo

Answer 2

尝试以下操作：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.Net;

namespace ConsoleApplication1
{
    class Program
    {
        const string URL = @"http://musicbrainz.org/ws/2/release-group/?query=artist:%22coldplay%22%20AND%20primarytype:%22single%22";
        static void Main(string[] args)
        {
            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(URL);
            request.UserAgent = "Hello World Super Script";
            HttpWebResponse response = (HttpWebResponse)request.GetResponse();
            XDocument doc = XDocument.Load(response.GetResponseStream());
            XNamespace ns = doc.Root.GetDefaultNamespace();

            List<Group> groups = doc.Descendants(ns + "release-group").Select(x => new Group()
            {
                title = (string)x.Element(ns + "title"),
                name = (string)x.Descendants(ns + "name").FirstOrDefault(),
                releaseTitles = x.Element(ns + "release-list").Descendants(ns + "title").Select(y => (string)y).ToArray()
            }).ToList();
        }
    }
    public class Group
    {
        public string title { get; set; }
        public string name { get; set; }
        public string[] releaseTitles { get; set; }
    }
}

使用 XML 从 Element 获取值

Getting value from Element with XML

c#

xml

linq-to-xml