我如何在 Rust 中 handle/circumvent "Cannot assign to ... which is behind a & reference"?
How do I handle/circumvent "Cannot assign to ... which is behind a & reference" in Rust?
我要实现一个简单的链表。这是我到目前为止的(工作)代码:
pub struct LinkedList<T> {
start: Option<Box<Link<T>>>,
}
impl<T> LinkedList<T> {
pub fn new() -> LinkedList<T> {
return LinkedList { start: None };
}
}
struct Link<T> {
value: Box<T>,
next: Option<Box<Link<T>>>,
}
impl<T> Link<T> {
fn new_end(value: T) -> Link<T> {
return Link::new(value, None);
}
fn new(value: T, next: Option<Box<Link<T>>>) -> Link<T> {
return Link {
value: Box::new(value),
next,
};
}
}
列表的下一个是附加到列表的方法;这是我想出的:
pub fn append(&mut self, element: T) {
// Create the link to append
let new_link = Some(Box::new(Link::new_end(element)));
// Find the last element of the list. None, if the list is empty
let mut last = &self.start;
while let Some(link) = last {
last = &link.next;
}
// Insert the new link at the correct position
match last {
None => self.start = new_link,
Some(last) => last.next = new_link, // This fails
}
}
准确的编译器错误是
error[E0594]: cannot assign to `last.next` which is behind a `&` reference
我隐约明白了问题;你不能改变一个不可变的引用。但是使引用可变似乎会使错误变得更糟。
如何处理这些类型的错误?有没有简单的快速修复方法,或者您在 Rust 中构建完全不同的代码?
您的代码几乎可以正常工作。如果你 bind mutably:
impl<T> LinkedList<T> {
pub fn append(&mut self, element: T) {
// Create the link to append
let new_link = Some(Box::new(Link::new_end(element)));
// Find the last element of the list. None, if the list is empty
let mut last = &mut self.start;
while let Some(link) = last {
last = &mut link.next;
}
// Insert the new link at the correct position
match last {
None => self.start = new_link,
Some(ref mut last) => last.next = new_link,
}
}
}
仅供参考, 非常擅长阐明 Rust 中有关可变性、类型和绑定的问题。
我要实现一个简单的链表。这是我到目前为止的(工作)代码:
pub struct LinkedList<T> {
start: Option<Box<Link<T>>>,
}
impl<T> LinkedList<T> {
pub fn new() -> LinkedList<T> {
return LinkedList { start: None };
}
}
struct Link<T> {
value: Box<T>,
next: Option<Box<Link<T>>>,
}
impl<T> Link<T> {
fn new_end(value: T) -> Link<T> {
return Link::new(value, None);
}
fn new(value: T, next: Option<Box<Link<T>>>) -> Link<T> {
return Link {
value: Box::new(value),
next,
};
}
}
列表的下一个是附加到列表的方法;这是我想出的:
pub fn append(&mut self, element: T) {
// Create the link to append
let new_link = Some(Box::new(Link::new_end(element)));
// Find the last element of the list. None, if the list is empty
let mut last = &self.start;
while let Some(link) = last {
last = &link.next;
}
// Insert the new link at the correct position
match last {
None => self.start = new_link,
Some(last) => last.next = new_link, // This fails
}
}
准确的编译器错误是
error[E0594]: cannot assign to `last.next` which is behind a `&` reference
我隐约明白了问题;你不能改变一个不可变的引用。但是使引用可变似乎会使错误变得更糟。
如何处理这些类型的错误?有没有简单的快速修复方法,或者您在 Rust 中构建完全不同的代码?
您的代码几乎可以正常工作。如果你 bind mutably:
impl<T> LinkedList<T> {
pub fn append(&mut self, element: T) {
// Create the link to append
let new_link = Some(Box::new(Link::new_end(element)));
// Find the last element of the list. None, if the list is empty
let mut last = &mut self.start;
while let Some(link) = last {
last = &mut link.next;
}
// Insert the new link at the correct position
match last {
None => self.start = new_link,
Some(ref mut last) => last.next = new_link,
}
}
}
仅供参考,