在 .eslintrc.json 中设置规则选项
set options for rule in .eslintrc.json
我想使用 this rule with the ignoreParameters option set to false. My eslint is configured with a .eslintrc.json
file and I can't manage to find how to set the options for a rule in this file. I've looked the doc and googled, and I looked at ,但我找不到如何使用 eslint 和 .eslintrc.json
文件为规则设置选项的示例。
这是我尝试添加此规则之前的 .eslintrc.json
文件(已应用该规则,但使用默认选项而不是我想要的选项):
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2
}
}
这是我尝试过的方法,总是导致规则不再适用(出现错误 Definition for rule '@typescript-eslint/no-inferable-types' was not found @typescript-eslint/no-inferable-types
):
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2,
"@typescript-eslint/no-inferable-types": [
"error",
{
"ignoreParameters": true
}
]
}
}
或:
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2,
"@typescript-eslint/no-inferable-types": [
2,
{
"ignoreParameters": true,
"ignoreProperties": false
}
]
}
}
感谢您的帮助。
所以我尝试的所有事情实际上都使用了正确的语法(我仍然会提出这个问题,因为我没有找到带有选项的 .eslinrc.json
文件示例的明确资源,导致我在错误的地方搜索问题)。
我的问题是我试图更改规则 no-inferrable-types
并且我在我的 .eslintrc.json
文件 no-inferable-types
中写了规则(少了一个 "r")。
因此我的(工作).eslintrc.json
是这样的:
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2,
"@typescript-eslint/no-inferrable-types": [
2,
{
"ignoreParameters": true
}
]
}
}
我想使用 this rule with the ignoreParameters option set to false. My eslint is configured with a .eslintrc.json
file and I can't manage to find how to set the options for a rule in this file. I've looked the doc and googled, and I looked at .eslintrc.json
文件为规则设置选项的示例。
这是我尝试添加此规则之前的 .eslintrc.json
文件(已应用该规则,但使用默认选项而不是我想要的选项):
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2
}
}
这是我尝试过的方法,总是导致规则不再适用(出现错误 Definition for rule '@typescript-eslint/no-inferable-types' was not found @typescript-eslint/no-inferable-types
):
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2,
"@typescript-eslint/no-inferable-types": [
"error",
{
"ignoreParameters": true
}
]
}
}
或:
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2,
"@typescript-eslint/no-inferable-types": [
2,
{
"ignoreParameters": true,
"ignoreProperties": false
}
]
}
}
感谢您的帮助。
所以我尝试的所有事情实际上都使用了正确的语法(我仍然会提出这个问题,因为我没有找到带有选项的 .eslinrc.json
文件示例的明确资源,导致我在错误的地方搜索问题)。
我的问题是我试图更改规则 no-inferrable-types
并且我在我的 .eslintrc.json
文件 no-inferable-types
中写了规则(少了一个 "r")。
因此我的(工作).eslintrc.json
是这样的:
{
"parser": "@typescript-eslint/parser",
"extends": [
"react-app",
"eslint:recommended",
"plugin:@typescript-eslint/recommended",
"prettier/@typescript-eslint",
"plugin:prettier/recommended"
],
"rules": {
"@typescript-eslint/explicit-function-return-type": 0,
"@typescript-eslint/no-explicit-any": 0,
"no-return-await": 2,
"curly": 2,
"@typescript-eslint/no-inferrable-types": [
2,
{
"ignoreParameters": true
}
]
}
}