如何显示使用实例化输入的值?
How can I display the values that I input using instantiation?
如何修改else if
中的代码,使我在if
中输入的内容在条件2中显示?
import java.util.*;
public class REPORTS
{
public static void main(String[]args)
{
int Studentid,equipid,quantity,studentid,equipid1;
String Studentname,Studentcourse,Studentlevel,equipmentname,reservationdate,returndate;
STUDENT stud=new STUDENT(1234,"abc","abc","abc");
EQUIPMENT equip;
RESERVATION reserve;
Scanner in = new Scanner(System.in);
int x = choices();
if(x==1)
{
System.out.println("Enter Student ID:");
Studentid=in.nextInt();
in.nextLine();
System.out.println("Enter Student Name:");
Studentname=in.nextLine();
System.out.println("Enter Student Course:");
Studentcourse=in.nextLine();
System.out.println("Enter Student Level:");
Studentlevel=in.nextLine();
stud.setID(Studentid);
stud.setName(Studentname);
stud.setCourse(Studentcourse);
stud.setLevel(Studentlevel);
}
else if(x==2)
{
stud.display();
}
}
我正在考虑使用循环,但我不知道如何正确循环才能获取用户在 if
语句中输入的数据。
我将 if else
更改为 switch
并尝试了 while
循环。但是程序无休止地运行,而不是显示我输入的内容,而是不断询问学生姓名:
while(x!=7)
{
switch(x)
{
case 1:
{
stud.getData();
choices();
break;
}
case 2:
{
stud.display();
break;
}
}
}
几个起点:
public static void main(String[]args)
{
int Studentid,equipid,quantity,studentid,equipid1;
String Studentname, Studentcourse, Studentlevel, equipmentname,
reservationdate, returndate;
STUDENT stud=new STUDENT(1234,"abc","abc","abc");
...
将您的 STUDENT class 重命名为 Student。此外,您不需要所有这些局部变量,它们只会让您的代码更难阅读。
为 Student
提供默认构造函数
public static void main(String[]args)
{
Student stud=new Student(); // call the default constructor, don't enter bogus data
Scanner in = new Scanner(System.in);
int x = choices();
while (x != 7) {
switch(x) {
case 1:
System.out.println("Enter Student ID:");
stud.setID(in.nextInt());
in.nextLine();
System.out.println("Enter Student Name:");
stud.setName(in.nextLine());
System.out.println("Enter Student Course:");
stud.setCourse(in.nextLine());
System.out.println("Enter Student Level:");
stud.setLevel(in.nextLine());
break;
case 2: stud.display(); break;
}
// this must be inside the loop!!
x = choices();
}
}
如何修改else if
中的代码,使我在if
中输入的内容在条件2中显示?
import java.util.*;
public class REPORTS
{
public static void main(String[]args)
{
int Studentid,equipid,quantity,studentid,equipid1;
String Studentname,Studentcourse,Studentlevel,equipmentname,reservationdate,returndate;
STUDENT stud=new STUDENT(1234,"abc","abc","abc");
EQUIPMENT equip;
RESERVATION reserve;
Scanner in = new Scanner(System.in);
int x = choices();
if(x==1)
{
System.out.println("Enter Student ID:");
Studentid=in.nextInt();
in.nextLine();
System.out.println("Enter Student Name:");
Studentname=in.nextLine();
System.out.println("Enter Student Course:");
Studentcourse=in.nextLine();
System.out.println("Enter Student Level:");
Studentlevel=in.nextLine();
stud.setID(Studentid);
stud.setName(Studentname);
stud.setCourse(Studentcourse);
stud.setLevel(Studentlevel);
}
else if(x==2)
{
stud.display();
}
}
我正在考虑使用循环,但我不知道如何正确循环才能获取用户在 if
语句中输入的数据。
我将 if else
更改为 switch
并尝试了 while
循环。但是程序无休止地运行,而不是显示我输入的内容,而是不断询问学生姓名:
while(x!=7)
{
switch(x)
{
case 1:
{
stud.getData();
choices();
break;
}
case 2:
{
stud.display();
break;
}
}
}
几个起点:
public static void main(String[]args)
{
int Studentid,equipid,quantity,studentid,equipid1;
String Studentname, Studentcourse, Studentlevel, equipmentname,
reservationdate, returndate;
STUDENT stud=new STUDENT(1234,"abc","abc","abc");
...
将您的 STUDENT class 重命名为 Student。此外,您不需要所有这些局部变量,它们只会让您的代码更难阅读。 为 Student
提供默认构造函数 public static void main(String[]args)
{
Student stud=new Student(); // call the default constructor, don't enter bogus data
Scanner in = new Scanner(System.in);
int x = choices();
while (x != 7) {
switch(x) {
case 1:
System.out.println("Enter Student ID:");
stud.setID(in.nextInt());
in.nextLine();
System.out.println("Enter Student Name:");
stud.setName(in.nextLine());
System.out.println("Enter Student Course:");
stud.setCourse(in.nextLine());
System.out.println("Enter Student Level:");
stud.setLevel(in.nextLine());
break;
case 2: stud.display(); break;
}
// this must be inside the loop!!
x = choices();
}
}