Google 表格填写来自 Java

Question

我需要用我的 Java 代码填写基本的 Google 表单，但它抛出 org.apache.http.client.ClientProtocolException: Unexpected response status: 405

这是我的代码：

private boolean sendMessage(UserInfo userInfo) {
    final HttpPost req = new HttpPost("my-form-url");
    try (CloseableHttpClient httpclient = HttpClients.createDefault()) {

        List<NameValuePair> form = new ArrayList<>();
        form.add(new BasicNameValuePair("entry.1301726507", userInfo.getName()));
        form.add(new BasicNameValuePair("entry.1466759457", "hello"));
        UrlEncodedFormEntity entity = new UrlEncodedFormEntity(form, Consts.UTF_8);

        req.setEntity(entity);
        System.out.println("Executing request " + req.getRequestLine());

        ResponseHandler<String> responseHandler = response -> {
            int status = response.getStatusLine().getStatusCode();
            if (status >= 200 && status < 300) {
                HttpEntity responseEntity = response.getEntity();
                return responseEntity != null ? EntityUtils.toString(responseEntity) : null;
            } else {
                throw new ClientProtocolException("Unexpected response status: " + status);
            }
        };
        String responseBody = httpclient.execute(req, responseHandler);
        System.out.println("----------------------------------------");
        System.out.println(responseBody);
        return true;
    } catch (IOException e) {
        e.printStackTrace();
        return false;
    }

这是表格：

我做错了什么？

Answer 1

您可以使用我的宠物项目为您完成这项工作：

添加依赖：

<dependency>
    <groupId>io.github.stepio.jgforms</groupId>
    <artifactId>jgforms</artifactId>
    <version>1.0.1</version>
</dependency>

定义表单：

public enum MyForm implements MetaData {

    USER_NAME(1301726507L),
    MESSAGE(1466759457L);

    private long id;

    JGForm(long id) {
        this.id = id;
    }

    @Override
    public long getId() {
        return this.id;
    }
}

填写表格并提交：

private boolean sendMessage(UserInfo userInfo) {
    URL url = Builder.formKey("my-form-key-from-url")
            .put(MyForm.USER_NAME, userInfo.getName())
            .put(MyForm.MESSAGE, "hello")
            .toUrl();
    Submitter submitter = new Submitter(
        new Configuration()
    );
    try {
       submitter.submitForm(url);
    } catch (NotSubmittedException ex) {
        // TODO: log & handle the exception properly
        return false;
    }
    return true;
}

查看 README 和单元测试以获取更多详细信息和示例：

https://github.com/stepio/jgforms

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