swift - '(AnyObject)' 不是 'NSObject' 的子类型
swift - '(AnyObject)' is not a subtype of 'NSObject'
我是 swift 开发的新手,我遵循了一个教程,一切都很好,直到我遇到这个错误,但我不知道如何修复它。
你能帮帮我吗?
if let json = response.result.value {
let jsonArray:NSArray = json as! NSArray
/// On fait la boucle pour avoir la liste globale des éléments a afficher
for i in 0..<jsonArray.count {
self.OPlays.append(Playlist(
title:(jsonArray[i] as AnyObject).value(forKey: "title") as? String,
artist:(jsonArray[i] as AnyObject).value(forKey: "artist") as? String,
categorie:(jsonArray[i] as AnyObject).value(forKey: "categorie") as? String,
cover_url:(jsonArray[i] as AnyObject).value(forKey: "cover_url") as? String)
)
}
self.tableViewPlaylist.reloadData()
}
新闻文件正确。
if let json = response.result.value {
let jsonArray:NSArray = json as! NSArray
/// On fait la boucle pour avoir la liste globale des éléments a afficher
for i in 0..<jsonArray.count {
self.OPlays.append(Playlist(
id: (jsonArray[i] as AnyObject).value(forKey: "id") as? Int,
title: (jsonArray[i] as AnyObject).value(forKey: "title") as? String,
artist: (jsonArray[i] as AnyObject).value(forKey: "artist") as? String,
cover_url: (jsonArray[i] as AnyObject).value(forKey: "cover_url") as? String,
categorie: (jsonArray[i] as AnyObject).value(forKey: "categorie") as? String
))
}
self.tableViewPlaylist.reloadData()
}
我会删除所有 AnyObject
代码:
if let array = response.result.value as? [[String: Any]] {
for dictionary in array {
self.OPlays.append(Playlist(
id: dictionary["id"] as? Int,
title: dictionary["title"] as? String,
artist: dictionary["artist"] as? String,
categorie: dictionary["categorie"] as? String,
cover_url: dictionary["cover_url"] as? String
))
}
self.tableViewPlaylist.reloadData
}
就个人而言,我会更进一步,不再手动解码您的 JSON。使用 JSONDecoder
.
struct Playlist: Codable {
let id: Int?
let title: String?
let artist: String?
let categorie: String?
let cover_url: String?
}
然后,假设您有 data
即展开的 Data
对象:
do {
self.OPlays = JSONDecoder().decode([Playlist].self, from: data)
} catch {
print(error)
}
或者,如果您使用的是 Alamofire,请考虑 Alamofire 5,它具有基于 JSONDecoder
的 response
方法。
我是 swift 开发的新手,我遵循了一个教程,一切都很好,直到我遇到这个错误,但我不知道如何修复它。 你能帮帮我吗?
if let json = response.result.value {
let jsonArray:NSArray = json as! NSArray
/// On fait la boucle pour avoir la liste globale des éléments a afficher
for i in 0..<jsonArray.count {
self.OPlays.append(Playlist(
title:(jsonArray[i] as AnyObject).value(forKey: "title") as? String,
artist:(jsonArray[i] as AnyObject).value(forKey: "artist") as? String,
categorie:(jsonArray[i] as AnyObject).value(forKey: "categorie") as? String,
cover_url:(jsonArray[i] as AnyObject).value(forKey: "cover_url") as? String)
)
}
self.tableViewPlaylist.reloadData()
}
新闻文件正确。
if let json = response.result.value {
let jsonArray:NSArray = json as! NSArray
/// On fait la boucle pour avoir la liste globale des éléments a afficher
for i in 0..<jsonArray.count {
self.OPlays.append(Playlist(
id: (jsonArray[i] as AnyObject).value(forKey: "id") as? Int,
title: (jsonArray[i] as AnyObject).value(forKey: "title") as? String,
artist: (jsonArray[i] as AnyObject).value(forKey: "artist") as? String,
cover_url: (jsonArray[i] as AnyObject).value(forKey: "cover_url") as? String,
categorie: (jsonArray[i] as AnyObject).value(forKey: "categorie") as? String
))
}
self.tableViewPlaylist.reloadData()
}
我会删除所有 AnyObject
代码:
if let array = response.result.value as? [[String: Any]] {
for dictionary in array {
self.OPlays.append(Playlist(
id: dictionary["id"] as? Int,
title: dictionary["title"] as? String,
artist: dictionary["artist"] as? String,
categorie: dictionary["categorie"] as? String,
cover_url: dictionary["cover_url"] as? String
))
}
self.tableViewPlaylist.reloadData
}
就个人而言,我会更进一步,不再手动解码您的 JSON。使用 JSONDecoder
.
struct Playlist: Codable {
let id: Int?
let title: String?
let artist: String?
let categorie: String?
let cover_url: String?
}
然后,假设您有 data
即展开的 Data
对象:
do {
self.OPlays = JSONDecoder().decode([Playlist].self, from: data)
} catch {
print(error)
}
或者,如果您使用的是 Alamofire,请考虑 Alamofire 5,它具有基于 JSONDecoder
的 response
方法。