构造函数和 g++ 编译配方的问题

Question

我正在使用适用于 C++11 的函数创建一个 cpp 程序。尽管代码看起来正确并且没有语法错误，但我在编译时收到此消息：

/tmp/cce9dpew.o: In function `Object::Object()':
classes.cpp:(.text+0xd): undefined reference to `vtable for Object'
/tmp/cce9dpew.o: In function `Object::~Object()':
classes.cpp:(.text+0x45): undefined reference to `vtable for Object'
/tmp/cce9dpew.o:(.rodata._ZTI6String[_ZTI6String]+0x10): undefined reference to `typeinfo for Object'
collect2: error: ld returned 1 exit status

我必须在这里补充一点，如果我将所有这些 .cpp 和 .h 文件放在一个文件中，它运行s Aok 打印构造函数和析构函数 cout 就可以了。有人可以帮忙吗？代码如下。 我曾经运行一起编译配方： g++ -std=c++0x classes.h classes.cpp mainiz.cpp

classes.h:

#ifndef CLASSES_H
#define CLASSES_H

#include <iostream>
#include <cstring>
using namespace std;

class Object
{
    private:
        int id;
    public:
        Object();
        ~Object();
        void set_id(int ids);
        int get_id();
        void Equal(Object* bj) const;
        void Identical(Object* bj) const;
        virtual Object* clone();
        virtual void toString();        
};


class String:public Object
{
        string characters;
    public:
        String();
        ~String();
        void set_char(string a);
        string get_char();
        String* clone();
        void toString();    
        int Length();
        void Clear(string a);
        string& Concat(string &a);
        char At(char b);
        string& UpdateAt(string a,string charact);
        void Print(const string a) const;   
};

#endif //CLASSES_H

classes.cpp:

#include <iostream>
#include <cstring>

#include "classes.h"

using namespace std;

//FOR OBJECT CLASS
Object::Object(){ cout << "An object just got created." << endl;}

Object::~Object(){ cout << "An object just got destroyed." << endl; }

void Object::set_id(int ids) { this->id = ids; }
int Object::get_id() { return this->id;}

void Object::Equal(Object* bj) const
{
    if((this->id == bj->id))
    {
        cout << "The objects are equal." << endl;
    }
    else
    {
        cout << "The objects are not equal." <<endl;
    }
}

void Object::Identical(Object* bj) const
{
    if(this==bj)
    {
        cout << "The objects are identical." <<endl;
    }
    else
    {
        cout << "The objects are not identical." <<endl;
    }
}

//FOR STRING CLASS
String::String(){ cout << "String just created" << endl;}

String::~String(){ cout << "String to be destroyed" << endl;}

void String::set_char(string a) { this->characters = a;}
string String::get_char() { return this->characters;}

String* String::clone() { return this;}
void String::toString() {cout << "characters" << endl;}

int String::Length()
{ 
    string a = this->characters;
    return a.length();  
}

void String::Clear(string a)
{
    this->characters.clear();
}

string& String::Concat(string &a){  return (this->characters.append(a));}

char String::At(char b) { return (this->characters.find(b)); }

string& String::UpdateAt(string a,string charact)
{
    int position=this->characters.find(charact);
    return this->characters.replace(position,1,a);  
}

void String::Print(const string a) const { cout << "print of string:" << a << endl; }

mainiz.cpp:

#include <iostream>
#include <cstring>

#include "classes.h"

using namespace std;

int main()
{
    Object k;
    Object *st = new String;
    String d;
}

Answer 1

Object::clone 和 Object::toString 已声明但从未实施。

如果您不想实现它们，请将它们设为纯虚拟的，如

class Object {
  virtual Object* clone() = 0;
};

Answer 2

为对象 class 创建析构函数 "virtual" 你会得到另一个关于 Object::clone 和 Object::toString.

未定义引用的错误

您可以尝试@Igor 建议的方法，但是您当前的 mainiz.cpp 代码将无法运行，因为 C++ 不允许 class 使用纯虚方法。

您可以试试下面的代码：

class Object {
  virtual ~Object();

  virtual Object* clone();
  virtual void toString();
};

Object* Object::clone() {
  // Make your implementation here
  return nullptr;
}

void Object::toString() {
  // Make your implementation here
}

Answer 3

None 上面给出的解决方案是 correct.The 问题在我的编译中 recipe.These 函数在 C++11 之后开始存在所以如果你使用类似的东西你的编译食谱应该是：

g++ -g -std=c++11 -o executable file.cpp main.cpp

构造函数和 g++ 编译配方的问题

problem with constructors and g++ compile recipe

c++

inheritance

compiler-errors

g++

class