mysql 中的复杂旋转
Complex pivoting in mysql
我在 MySQL 中有一个 table 有数据,我想从 table 实现某种旋转,这对我来说变得很复杂。我已经尝试调查 this 但似乎对我没有任何帮助。这是我的 table 的结构:
roomid| day| 1 | 2 | 3 | 4 | 5 | 6 |
------+----+---+---+---+---+---+---+
1 | 1 |BIO| | | | | |
1 | 2 | |CHE| | | | |
1 | 3 | | | | | |ENG|
1 | 4 | | |KIS| | | |
1 | 5 | | | | | |PHY|
2 | 1 |BIO| | | | | |
2 | 2 | |CHE| | | | |
2 | 3 | | | | |ENG| |
2 | 4 | | |KIS| | | |
2 | 5 | | | | | |PHY|
这个table是holding timetable的数据,roomid是房间的id,day是周一到周五(1到5)的天数。 1 到 6 列是周期 ID。
我需要组织数据以获得每天显示每个 class 期间 ID 的结果。像这样:
|roomid| 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 |
-------+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+
1 |BIO| | | | | | |CHE| | | | | | | | | |ENG| | |KIS| | | | | | | | |PHY|
2 |BIO| | | | | | |CHE| | | | | | | | | |ENG| | |KIS| | | | | | | | |PHY|
请注意,周期 ID 会在不同的日子重复出现。
您可以使用条件聚合:
select room_id,
max(case when day = 1 then slot_1 end) as day_1_slot_1,
max(case when day = 1 then slot_2 end) as day_1_slot_2,
. . .
max(case when day = 2 then slot_1 end) as day_2_slot_1,
max(case when day = 2 then slot_2 end) as day_2_slot_2,
. . .
from schedule s
group by room_id
虽然不声称是最终解决方案,但规范化设计可能如下所示。坦率地说,如果说现在的设计比这更合适,那就有点难以置信了。
+--------+-----+------+---------+
| roomid | day | slot | subject |
+--------+-----+------+---------+
| 1 | 1 | 1 | BIO |
| 2 | 1 | 2 | BIO |
| 1 | 2 | 2 | CHE |
| 2 | 2 | 2 | CHE |
| 1 | 4 | 3 | KIS |
| 2 | 4 | 3 | KIS |
| 2 | 3 | 5 | ENG |
| 1 | 3 | 6 | ENG |
| 1 | 5 | 6 | PHY |
| 2 | 5 | 6 | PHY |
+--------+-----+------+---------+
我在 MySQL 中有一个 table 有数据,我想从 table 实现某种旋转,这对我来说变得很复杂。我已经尝试调查 this 但似乎对我没有任何帮助。这是我的 table 的结构:
roomid| day| 1 | 2 | 3 | 4 | 5 | 6 |
------+----+---+---+---+---+---+---+
1 | 1 |BIO| | | | | |
1 | 2 | |CHE| | | | |
1 | 3 | | | | | |ENG|
1 | 4 | | |KIS| | | |
1 | 5 | | | | | |PHY|
2 | 1 |BIO| | | | | |
2 | 2 | |CHE| | | | |
2 | 3 | | | | |ENG| |
2 | 4 | | |KIS| | | |
2 | 5 | | | | | |PHY|
这个table是holding timetable的数据,roomid是房间的id,day是周一到周五(1到5)的天数。 1 到 6 列是周期 ID。 我需要组织数据以获得每天显示每个 class 期间 ID 的结果。像这样:
|roomid| 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 |
-------+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+
1 |BIO| | | | | | |CHE| | | | | | | | | |ENG| | |KIS| | | | | | | | |PHY|
2 |BIO| | | | | | |CHE| | | | | | | | | |ENG| | |KIS| | | | | | | | |PHY|
请注意,周期 ID 会在不同的日子重复出现。
您可以使用条件聚合:
select room_id,
max(case when day = 1 then slot_1 end) as day_1_slot_1,
max(case when day = 1 then slot_2 end) as day_1_slot_2,
. . .
max(case when day = 2 then slot_1 end) as day_2_slot_1,
max(case when day = 2 then slot_2 end) as day_2_slot_2,
. . .
from schedule s
group by room_id
虽然不声称是最终解决方案,但规范化设计可能如下所示。坦率地说,如果说现在的设计比这更合适,那就有点难以置信了。
+--------+-----+------+---------+
| roomid | day | slot | subject |
+--------+-----+------+---------+
| 1 | 1 | 1 | BIO |
| 2 | 1 | 2 | BIO |
| 1 | 2 | 2 | CHE |
| 2 | 2 | 2 | CHE |
| 1 | 4 | 3 | KIS |
| 2 | 4 | 3 | KIS |
| 2 | 3 | 5 | ENG |
| 1 | 3 | 6 | ENG |
| 1 | 5 | 6 | PHY |
| 2 | 5 | 6 | PHY |
+--------+-----+------+---------+