暂停 for 循环，保存进度并再次恢复？

Question

在 python(3) 中，我正在编写一个使用 递归 for 循环 的脚本（for 循环多次调用它自己的函数）而且我知道脚本只会在大约 45 小时后完成，所以我正在寻找一种方法将进度保存在文件中，关闭 python，关闭然后再恢复它天.

有没有办法保存进度然后在另一个（新）会话中恢复？

递归循环示例：

i=1
def for_loop(i):
    if i==10:
        print(i)
        #code
    else:
        for x in range(0, 10):
            #code
            for_loop(i+1)

完整代码：

def TheLoop(num_N, num_a, num_A, num_S, i):
    global Key
    global num_Keys
    global num_Declined
    global KeyTogether
    global f

    if i > 8:
        if (num_N > 0) and (num_a > 0) and (num_A > 0) and (num_S > 0):
            num_Keys = num_Keys + 1
            KeyTogether = ''
            for t in range(8):
                try:
                    number = int(Key[t])
                    Key[t] = str(Key[t])
                except ValueError:
                    pass
                KeyTogether += Key[t]
            #Output Key to a file
            f.write(KeyTogether + "\n")
        else:
            # Invalid Key
            num_Declined = num_Declined + 1
    else:
       if (num_N < 4) and ((i < 8) or ((num_a > 0) and (num_A > 0) and (num_S > 0))):
            num_N = num_N + 1
            for x in range(0, 10):
                Key[i-1] = x
                TheLoop(num_N, num_a, num_A, num_S, i+1)
       if (num_a < 4) and ((i < 8) or ((num_N > 0) and (num_A > 0) and (num_S > 0))):
            num_a = num_a +1
            for c in "abcdefghijklmnopqrstuvwxyz":
                Key[i-1] = c
                TheLoop(num_N, num_a, num_A, num_S, i+1)
       if (num_A < 4) and ((i < 8) or ((num_N > 0) and (num_a > 0) and (num_S > 0))):
            num_A = num_A + 1
            for c in "ABCDEFGHIJKLMNOPQRSTUVWXYZ":
                Key[i-1] = c
                TheLoop(num_N, num_a, num_A, num_S, i+1)
       if (num_S < 4) and ((i < 8) or ((num_N > 0) and (num_a > 0) and (num_A > 0))):
            num_S = num_S + 1
            for c in '"'"!#$%&'()*+,-./:;<=>?@[\]^_`{|}~":
                Key[i-1] = c
                TheLoop(num_N, num_a, num_A, num_S, i+1)

Start = time.time()
TheLoop(0,0,0,0,1)
duration = time.time() - Start
print("Duration: " + str(duration))
print("Declined Keys: ", num_Declined)
print("Valid Keys: ", num_Keys)
duracionstr = str(duration)
f.write("Duration: " + durationstr)

Answer 1

我在项目中的一些长运行循环中遇到了同样的问题。我创建了一个运行循环并具有一些额外优点的函数。

每 N 次迭代保存进度（pickle）
从上次中断的地方继续
如果输入包含多个可迭代对象，我将遍历它们的排列。
视觉效果不错的进度条。

如有任何问题，请告诉我，我很乐意提供帮助。

该函数在 pip 上可用：

pip install daves_utilities

用法：

from daves_utilities.for_long import for_long

letters = ["a","b","c","d"]
numbers = [10,20,40,100,500,1000]
attribute_dict = {"letters": letters, "numbers": numbers, "input_bool":True}

df_out = for_long(iter_fun = my_function, iter_attr = attribute_dict,\
                  save_every_n = 10, path = "./")

暂停 for 循环，保存进度并再次恢复？

Pause a for loop, save progress and resume it another time?

python

for-loop

progress

save