如何将编码更改为下载的文件 Kotlin

Question

我正在制作一个应用程序，它将下载一个 .zip 文件，将其解压缩，最后获取 .srt 文件（已压缩）并将其作为字幕文件放入 exoplayer 电影中。

我的问题

文件里面有希腊字母，当我把它作为字幕文件时，我只看到损坏的字母

我尝试了什么

下面是解压文件的代码

    fun writeZipAndUnZip(subtitlesLinks: ArrayList<String>, context: Context, body: ResponseBody?) {

    if (body == null) { return }

    val file = File(getSubsDirectory(), subtitlesLinks.first())

    var inputStream: InputStream? = null
    var outputStream: OutputStream? = null

    try {
        val fileReader = ByteArray(4096)

        inputStream = body.byteStream()
        outputStream = FileOutputStream(file)

        while (true) {
            var read = inputStream.read(fileReader)

            if (read == -1) {
                break
            }

            outputStream.write(fileReader, 0, read)
        }

        outputStream.flush()

        unzip(context)
    } catch (e: IOException) {
        return
    } finally {
        inputStream?.close()
        outputStream?.close()
    }}

fun unzip(context: Context) {

    val unzipPath = getSubsDirectory()
    var count: Int
    val buffer = ByteArray(4096)
    val subFile = File(getSubsDirectory()).listFiles()?.first() ?: return
    try {
        val stream = FileInputStream(subFile.absolutePath)

        ZipInputStream(stream).use { zis ->
            var ze = ZipEntry("")
            while (zis.nextEntry?.also { ze = it } != null) {
                var fileName = ze.name
                fileName = fileName.substring(fileName.indexOf("/") + 1)
                val file = File(unzipPath, fileName)
                val dir = if (ze.isDirectory) file else file.parentFile

                if (!dir.isDirectory && !dir.mkdirs())
                    throw FileNotFoundException("Invalid path: " + dir.absolutePath)
                if (ze.isDirectory) continue
                val fileOutput = FileOutputStream(file)
                try {
                    while (zis.read(buffer).also { count = it } != -1)
                        fileOutput.write(buffer, 0, count)
                } catch (e: IOException) {
                    Timber.tag("ErrorZip").d(e.localizedMessage)
                } finally {
                    val fileOutput = context.openFileOutput(fileName, Context.MODE_PRIVATE)
                    fileOutput.close()
                }
            }
        }

    } catch (e: IOException) {
        Timber.tag("ErrorZip").d(e.localizedMessage)
    }}

这是我在exoplayer中放字幕的代码

 val subtitleFormat = Format.createTextSampleFormat(null, MimeTypes.APPLICATION_SUBRIP, Format.NO_VALUE, "el")
    val subtitleSource = SingleSampleMediaSource(File(Utils.getSubsDirectory()).listFiles()!![1].toUri(), dataSourceFactory, subtitleFormat, C.TIME_UNSET)
    mediaSource = MergingMediaSource(buildMediaSource(videoUrl), subtitleSource)

我也尝试使用 Utf-8 编码重新保存字幕，但我得到了一些希腊字符，使用此代码最丢失或不正确

fun encode() {
        val charset = "UTF8"

        val subFile = File(getSubsDirectory()).listFiles()!![1] ?: return

        val inputStream: InputStream = subFile.absoluteFile.inputStream()
        val inputString = inputStream.bufferedReader().use { it.readText() }

        val writer = OutputStreamWriter(FileOutputStream(File(getSubsDirectory(), "subs.srt")), charset)
        writer.write(inputString)
        writer.close()
    }

Answer 1

您尝试读取的文件的编码可能与系统默认的编码不同（Android 使用 utf-8）。您需要以 'correct' 编码格式（希腊语通常是 Windows-1253）读取文件，然后将其保存为 utf-8.

如何将编码更改为下载的文件 Kotlin

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