如何从简单类型的方法访问值？

Question

如果我想创建我的简单类型，我如何从类型方法访问它的值？
例如：

[IntegerType (rank = 6, signed = true, width = 32)]
[SimpleType]
[CCode (has_type_id = false)]
struct foo_t {
    public string say_hello(){
        return(@"Hello from new foo_t type");
    }
    public int x10(){
        return this.value * 10;
    }
}

这里this.value报错The name 'value' does not exist.
say_hello 工作正常。

Answer 1

答案非常简单，没有隐藏的value字段，只有this是当前值。

[IntegerType (rank = 6, signed = true, width = 32)]
[SimpleType]
[CCode (has_type_id = false)]
struct foo_t {
    public int x10(){
        return this * 10;
    }
}
void main () {
    foo_t foo = 5;
    prin(foo.x10());
}


[Print]
inline void prin (string str) {
    stdout.printf (str + "\n");
}

工作正常！

如何从简单类型的方法访问值？

How do I access a value from a method of my simple type?

glib

vala