如何围绕 pygame 中的轴心点旋转元素？

Question

我正在尝试围绕枢轴点旋转 pygame 中的元素（在我的例子中是字体）我的代码如下：

    import pygame, time

    pygame.init()

    display_width = 800
    display_height = 800

    window = pygame.display.set_mode((display_width, display_height))
    pygame.display.set_caption("Dials")

    black = (0, 0, 0)
    white = (255, 255, 255)
    red = (255, 0, 0)
    green = (0, 255, 0)
    blue = (0, 0, 255)


clock = pygame.time.Clock()

font = pygame.font.SysFont('Arial', 50, True)

#All Images of Dials

tutorial = [pygame.image.load('Dial_Images/tutorial_base.png')]

tutorialInputs = [[1,4,3,4], [1,4,3,2], [1,4,3,2], [1,4,3,4]]

class Dial:
    def __init__(self, x, y, radius, inputs):
        self.x = x
        self.y = y
        self.radius = radius
        self.inputs = inputs
        self.columns = len(self.inputs)
        self.rows = len(self.inputs[0])

    def drawDial(self):
        for i in range(0, self.columns):
            pygame.draw.circle(window, red, (self.x, self.y), self.radius)
            pygame.draw.circle(window, black, (self.x, self.y), self.radius, 1)

        if self.rows == 4:
            input_1 = font.render(str(self.inputs[0][0]), 1, black)
            input_2 = font.render(str(self.inputs[0][1]), 1, black)
            input_3 = font.render(str(self.inputs[0][2]), 1, black)
            input_4 = font.render(str(self.inputs[0][3]), 1, black)

            window.blit(input_1, (self.x - 4, self.y - self.radius + 10))
            window.blit(input_2, (self.x + self.radius - 35, self.y - 15))
            window.blit(input_3, (self.x - 4, self.y + self.radius - 40))
            window.blit(input_4, (self.x - self.radius + 20, self.y - 15))




def level_1():
   window.fill(white)
   dial1.drawDial()


#all Dials Instantiated

dial1 = Dial(int(display_width/2), int(display_height/2), int((display_width/2) - 100), tutorialInputs)

score = 0

run = True
level1 = True

while run:
    keys = pygame.key.get_pressed()

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False
    pygame.display.update()
    clock.tick(100)

    if level1:
        level_1()



pygame.quit()

下面将在12点、3点、6点和9点创建一个window和一个黑色边框的圆圈和4个数字。

我想围绕圆心旋转输入。允许我旋转 input_1 - 输入的任何 pygame 函数 _4 绕圆心90度？我在 pygame 上看到了一些函数，例如 pygame.math.vector 和其他一些 .rotate 函数，但我想要最好的方法。

此外，如果有一种方法可以清理我对输入位置进行编码的方式，使它们在 12 点、3 点、6 点和 9 点对齐，那么有帮助。

Answer 1

仅在 image/surface 中引用文本，因此您可以使用 pygame 的功能来原地旋转图像（围绕图像中心）

image = pygame.transform.rotate(image, -angle)

然后使用 radius 和 angle 从圆心

开始将其移动到圆的边界

angle = 0 # 90, 180, 270
x = dial_center_x
y = dial_center_y
x += radius * sin(radians(angle))
y += radius * cos(radians(angle))

最好使用 pygame.Rect() 来保持位置和大小 - 它具有 .x、.y 以及 .center、.centerx 等属性.centery 这样很容易将数字放在拨号盘的中心

image_rect = image.get_rect()

image_rect.center = dial_rect.center

然后可以用radius和angle移动到12点、3点、6点、9点甚至1点的位置'时钟，2 点钟等

angle = 0 # 90, 180, 270
image_rect.centerx += radius * sin(radians(angle))
image_rect.centery += radius * cos(radians(angle))

import pygame
import time
import math

# --- constants --- (UPPER_CASE_NAMES)

BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
RED   = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE  = (0, 0, 255)

DISPLAY_WIDTH = 800
DISPLAY_HEIGHT = 800

# --- classes ---

class Dial:

    def __init__(self, x, y, radius, inputs, angle_step=45):
        self.rect = pygame.Rect(x-radius, y-radius, 2*radius, 2*radius)
        self.radius = radius
        self.radius2 = radius - 30 # position for digits
        self.inputs = inputs
        self.angle_step = angle_step

    def draw(self): # no need to add prefix/postfix 'Dial' to name `draw`
        #for i in range(0, self.columns):
        # `Dial` means single object so it should draw only one circle 
        pygame.draw.circle(window, RED, self.rect.center, self.radius)
        pygame.draw.circle(window, BLACK, self.rect.center, self.radius, 1)

        angle = 0
        for number in self.inputs:
            text = font.render(str(number), 1, BLACK)

            # rotate image
            text = pygame.transform.rotate(text, -angle)

            # center image on circle
            text_rect = text.get_rect(center=self.rect.center)

            # move to border using `angle` and `radius`
            angle_rad = math.radians(180-angle)
            text_rect.centerx += self.radius2 * math.sin(angle_rad)
            text_rect.centery += self.radius2 * math.cos(angle_rad)

            window.blit(text, text_rect)

            angle += self.angle_step


# --- functions ---

def level_1():
   window.fill(WHITE)
   dial1.draw()
   dial2.draw()
   dial3.draw()

# --- main ---

pygame.init()

window = pygame.display.set_mode((DISPLAY_WIDTH, DISPLAY_HEIGHT))
window_rect = window.get_rect()

pygame.display.set_caption("Dials")

clock = pygame.time.Clock()

font = pygame.font.SysFont('Arial', 50, True)

#tutorial = [pygame.image.load('Dial_Images/tutorial_base.png')]

tutorial_inputs = [[1,4,3,4], [1,4,3,2], [1,4,3,2], [1,4,3,4]]

dial1 = Dial(window_rect.centerx, window_rect.centery, window_rect.centerx-250, tutorial_inputs[0], 45)
dial2 = Dial(window_rect.centerx-250, window_rect.centery-250, window_rect.centerx-250, tutorial_inputs[1], 90)
dial3 = Dial(window_rect.centerx+250, window_rect.centery-250, window_rect.centerx-250, tutorial_inputs[2], 30)

score = 0

run = True
level1 = True

while run:
    #keys = pygame.key.get_pressed()

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    pygame.display.update()
    clock.tick(100)

    if level1:
        level_1()

pygame.quit()

如何围绕 pygame 中的轴心点旋转元素？

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python

python-3.x

pygame

pygame-surface

pygame-tick