Spring - 如何为 soap 服务构建 junit 测试

Question

我正在按照 spring 指南创建一个 hello world soap ws。下面的link：

https://spring.io/guides/gs/producing-web-service/

我成功让它工作了。当我运行这个命令行 :

curl --header "content-type: text/xml" -d @src/test/resources/request.xml http://localhost:8080/ws/coutries.wsdl

我收到了这个回复。

<SOAP-ENV:Header/><SOAP-ENV:Body><ns2:getCountryResponse xmlns:ns2="http://spring.io/guides/gs-producing-web-service"><ns2:country><ns2:name>Spain</ns2:name><ns2:population>46704314</ns2:population><ns2:capital>Madrid</ns2:capital><ns2:currency>EUR</ns2:currency></ns2:country></ns2:getCountryResponse></SOAP-ENV:Body></SOAP-ENV:Envelope>

现在我正在尝试为此服务（控制器层）创建一个 junit 测试，但它不起作用。

这是我的单元测试：

@RunWith(SpringRunner.class)
@WebMvcTest(CountryEndpoint.class)
@ContextConfiguration(classes = {CountryRepository.class, WebServiceConfig.class})
public class CountryEndpointTest {

    private final String URI = "http://localhost:8080/ws/countries.wsdl";

    @Autowired
    private MockMvc mockMvc;

    @Test
    public void test() throws Exception {


        mockMvc.perform(

                get(URI)
                        .accept(MediaType.TEXT_XML)
                        .contentType(MediaType.TEXT_XML)
                        .content(request)

        )
                .andDo(print())
                .andExpect(status().isOk());
    }

    static String request = "<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\"\n" +
            "                  xmlns:gs=\"http://spring.io/guides/gs-producing-web-service\">\n" +
            "    <soapenv:Header/>\n" +
            "    <soapenv:Body>\n" +
            "        <gs:getCountryRequest>\n" +
            "            <gs:name>Spain</gs:name>\n" +
            "        </gs:getCountryRequest>\n" +
            "    </soapenv:Body>\n" +
            "</soapenv:Envelope>";
}

这是错误：

MockHttpServletResponse:
           Status = 404
    Error message = null
          Headers = {}
     Content type = null
             Body = 
    Forwarded URL = null
   Redirected URL = null
          Cookies = []

java.lang.AssertionError: Status 
Expected :200
Actual   :404

我将日志级别更改为调试，我发现了这个：

2020-01-27 18:04:11.880  INFO 32723 --- [           main] c.s.t.e.s.endpoint.CountryEndpointTest   : Started CountryEndpointTest in 1.295 seconds (JVM running for 1.686)
2020-01-27 18:04:11.925 DEBUG 32723 --- [           main] s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /ws/countries.wsdl
2020-01-27 18:04:11.929 DEBUG 32723 --- [           main] s.w.s.m.m.a.RequestMappingHandlerMapping : Did not find handler method for [/ws/countries.wsdl]
2020-01-27 18:04:11.930 DEBUG 32723 --- [           main] o.s.w.s.handler.SimpleUrlHandlerMapping  : Matching patterns for request [/ws/countries.wsdl] are [/**]
2020-01-27 18:04:11.930 DEBUG 32723 --- [           main] o.s.w.s.handler.SimpleUrlHandlerMapping  : URI Template variables for request [/ws/countries.wsdl] are {}
2020-01-27 18:04:11.931 DEBUG 32723 --- [           main] o.s.w.s.handler.SimpleUrlHandlerMapping  : Mapping [/ws/countries.wsdl] to HandlerExecutionChain with handler [ResourceHttpRequestHandler [locations=[ServletContext resource [/], class path resource [META-INF/resources/], class path resource [resources/], class path resource [static/], class path resource [public/]], resolvers=[org.springframework.web.servlet.resource.PathResourceResolver@c7a977f]]] and 1 interceptor

我尝试了另一种解决方案（如下），但它也不起作用。

@RunWith(SpringRunner.class)
@ContextConfiguration(classes = {WebServiceConfig.class, CountryRepository.class})
public class CountryEndpointTest {

    private final String URI = "http://localhost:8080/ws/countries.wsdl";

    private MockMvc mockMvc;

    @Autowired
    CountryRepository countryRepository;


    @Before
    public void setup() {
        this.mockMvc = standaloneSetup(new CountryEndpoint(countryRepository)).build();
    }

Answer 1

请将 GET 方法更改为 POST。

mockMvc.perform(

                postURI) // <-- This line!!!
                        .accept(MediaType.TEXT_XML)
                        .contentType(MediaType.TEXT_XML)
                        .content(request)

Answer 2

如果您使用 spring ws 框架来实现您的端点，请参阅 spring-ws-test。您会发现一个模拟客户端并测试您的端点的 MockWebServiceClient。我建议你看看这个例子：https://memorynotfound.com/spring-ws-server-side-integration-testing/

这仅适用于 spring 网络服务，不适用于 CXF 网络服务。

Answer 3

Spring 文档说： https://docs.spring.io/spring-boot/docs/2.1.5.RELEASE/reference/html/boot-features-testing.html

By default, @SpringBootTest will not start a server.

你需要定义

@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.RANDOM_PORT)

到运行服务器。

我尝试使用模拟服务器，但我无法访问端点（即使使用 WebEnvironment.DEFINED_PORT）

所以我做了如下：

@RunWith(SpringRunner.class)
@ActiveProfiles("test")
@SpringBootTest(webEnvironment = SpringBootTest.WebEnvironment.RANDOM_PORT)
@AutoConfigureWebTestClient
public class FacturationEndpointTest {

@Autowired
private WebTestClient webClient;

@Test
public void testWSDL() throws Exception {

    this.webClient.get().uri("/test_service/services.wsdl")
            .exchange().expectStatus().isOk();

}

如果你想像我一样使用 WebTestClient，你需要在 pom.xml 中添加以下依赖项：

<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-webflux</artifactId>
    <scope>test</scope>
</dependency>

Spring - 如何为 soap 服务构建 junit 测试

Spring - How to build a junit test for a soap service

junit

spring-mvc

spring-test-mvc

spring-boot