根据产品类别拆分采购订单
Split Purchase Order according to Product Category
我想根据产品类别拆分采购订单。
到目前为止我的代码:
_inherit ='purchase.order.line'
split = fields.Boolean(string='Split')
_inherit ='purchase.order'
def btn_split_rfq(self):
flag = []
for record in self:
if record.order_line:
for rec in record.order_line:
rec.split = True # oles tis eggrafes true
flag.append(rec.product_id.categ_id.id) # lista me ta categ ids
newlist=[ii for n,ii in enumerate(flag) if ii not in flag[:n]] # ta krata mono mia fora an uparxoun polles
for index in newlist: # gia 2 katigories 8a treksi 2 fores
quotation_id = self.copy()
for index in record.order_line:
if index.split:
self.env['purchase.order.line'].browse(index.id).unlink()
else:
raise ValidationError(_('Please Select Order Line To Split'))
到目前为止,代码已拆分为多个采购订单,例如如果我有 2 种类型的类别正在制作 2 个 PO,但两个 PO 正在使用并且 4 个产品不仅属于产品类别(见下图)。
输出:
但我想要这种输出:
有什么解决办法吗?
我试图忽略你的代码示例,因为它对我来说很难理解。如果你想试试我的尝试:
def button_split_by_prod_categ(self):
self.ensure_one()
groups = {}
# group lines by product category
for line in self.order_line:
if line.product_id.categ_id not in groups:
groups[line.product_id.categ_id] = line
else:
groups[line.product_id.categ_id] =| line
skip = True
orders = self
for lines in groups.values():
# skip first group
if skip:
skip = False
continue
# or create a new order without lines and connect
# the group's lines with it
else:
default_values = {'order_line': []}
new_order = self.copy(default=default_values)
lines.write({'order_id': new_order.id})
orders |= new_order
# now you could return a list view with all orders
# or just do 'nothing'
return
我找到了我的问题的解决方案,我认为不是很好,但它确实有效。感谢@CZoellner 和@Charif DZ 的努力!!!
def btn_split_rfq(self):
flag =[]
for record in self:
if record.order_line:
for rec in record.order_line: #run for all products on purchase order
flag.append(rec.product_id.categ_id.id) # append product category ids
categ_ids=[ii for n,ii in enumerate(flag) if ii not in flag[:n]] # filter list,keep only one time every product category id
categ_ids.sort() # sorting list
for index in categ_ids: # will run 2 times if there is 2 product categories
quotations_ids = [self.copy()]
for order_line in quotations_ids:
prods = self.env['purchase.order.line'].search([('product_categ_id' ,'!=',index),('order_id','=',int(order_line))])
for ids in prods:
self.env['purchase.order.line'].browse(ids.id).unlink()
else:
raise ValidationError(_('Not Available Purchase Order Lines'))
我想根据产品类别拆分采购订单。
到目前为止我的代码:
_inherit ='purchase.order.line'
split = fields.Boolean(string='Split')
_inherit ='purchase.order'
def btn_split_rfq(self):
flag = []
for record in self:
if record.order_line:
for rec in record.order_line:
rec.split = True # oles tis eggrafes true
flag.append(rec.product_id.categ_id.id) # lista me ta categ ids
newlist=[ii for n,ii in enumerate(flag) if ii not in flag[:n]] # ta krata mono mia fora an uparxoun polles
for index in newlist: # gia 2 katigories 8a treksi 2 fores
quotation_id = self.copy()
for index in record.order_line:
if index.split:
self.env['purchase.order.line'].browse(index.id).unlink()
else:
raise ValidationError(_('Please Select Order Line To Split'))
到目前为止,代码已拆分为多个采购订单,例如如果我有 2 种类型的类别正在制作 2 个 PO,但两个 PO 正在使用并且 4 个产品不仅属于产品类别(见下图)。
输出:
但我想要这种输出:
有什么解决办法吗?
我试图忽略你的代码示例,因为它对我来说很难理解。如果你想试试我的尝试:
def button_split_by_prod_categ(self):
self.ensure_one()
groups = {}
# group lines by product category
for line in self.order_line:
if line.product_id.categ_id not in groups:
groups[line.product_id.categ_id] = line
else:
groups[line.product_id.categ_id] =| line
skip = True
orders = self
for lines in groups.values():
# skip first group
if skip:
skip = False
continue
# or create a new order without lines and connect
# the group's lines with it
else:
default_values = {'order_line': []}
new_order = self.copy(default=default_values)
lines.write({'order_id': new_order.id})
orders |= new_order
# now you could return a list view with all orders
# or just do 'nothing'
return
我找到了我的问题的解决方案,我认为不是很好,但它确实有效。感谢@CZoellner 和@Charif DZ 的努力!!!
def btn_split_rfq(self):
flag =[]
for record in self:
if record.order_line:
for rec in record.order_line: #run for all products on purchase order
flag.append(rec.product_id.categ_id.id) # append product category ids
categ_ids=[ii for n,ii in enumerate(flag) if ii not in flag[:n]] # filter list,keep only one time every product category id
categ_ids.sort() # sorting list
for index in categ_ids: # will run 2 times if there is 2 product categories
quotations_ids = [self.copy()]
for order_line in quotations_ids:
prods = self.env['purchase.order.line'].search([('product_categ_id' ,'!=',index),('order_id','=',int(order_line))])
for ids in prods:
self.env['purchase.order.line'].browse(ids.id).unlink()
else:
raise ValidationError(_('Not Available Purchase Order Lines'))