我怎样才能为字节文件自定义实现词袋？

Question

我正在尝试对字节文件中存在的十六进制代码自定义实现词袋。所以十六进制语料库将包含一个像“??”这样的字符。我找到了 Bow 自定义实现的代码，但它删除了“??”来自语料库。

# Replace all none alphanumeric characters with spaces
s="0,1,2,3,4,5,6,7,8,9,0a,0b,0c,0d,0e,0f,10,11,12,13,14,15,16,17,18,19,1a,1b,1c,1d,1e,1f,20,21,22,23,24,25,26,27,28,29,2a,2b,2c,2d,2e,2f,30,31,32,33,34,35,36,37,38,39,3a,3b,3c,3d,3e,3f,40,41,42,43,44,45,46,47,48,49,4a,4b,4c,4d,4e,4f,50,51,52,53,54,55,56,57,58,59,5a,5b,5c,5d,5e,5f,60,61,62,63,64,65,66,67,68,69,6a,6b,6c,6d,6e,6f,70,71,72,73,74,75,76,77,78,79,7a,7b,7c,7d,7e,7f,80,81,82,83,84,85,86,87,88,89,8a,8b,8c,8d,8e,8f,90,91,92,93,94,95,96,97,98,99,9a,9b,9c,9d,9e,9f,a0,a1,a2,a3,a4,a5,a6,a7,a8,a9,aa,ab,ac,ad,ae,af,b0,b1,b2,b3,b4,b5,b6,b7,b8,b9,ba,bb,bc,bd,be,bf,c0,c1,c2,c3,c4,c5,c6,c7,c8,c9,ca,cb,cc,cd,ce,cf,d0,d1,d2,d3,d4,d5,d6,d7,d8,d9,da,db,dc,dd,de,df,e0,e1,e2,e3,e4,e5,e6,e7,e8,e9,ea,eb,ec,ed,ee,ef,f0,f1,f2,f3,f4,f5,f6,f7,f8,f9,fa,fb,fc,fd,fe,ff,??"

import re

def generate_ngrams(s, n):
    # Convert to lowercases
    s = s.lower()

    s = re.sub(r'[^a-zA-Z0-9\s]', ' ', s)

    # Break sentence in the token, remove empty tokens
    tokens = [token for token in s.split(" ") if token != ""]

    # Use the zip function to help us generate n-grams
    # Concatentate the tokens into ngrams and return
    ngrams = zip(*[token[i:] for i in range(n)])
    return [" ".join(ngram) for ngram in ngrams]

删除此行：s = re.sub(r'[^a-zA-Z0-9\s]', ' ', s)，returns 什么都没有

Answer 1

正则表达式替换每个不是的字符（a-z、A-Z、0-9、任何白色space ) 与单个 space。这包括您要保留的 ?。将其添加到排除集

s = re.sub(r'[^a-zA-Z0-9\s?]', ' ', s)

使其正常工作（您还必须修复 token 中那个莫名其妙的拼写错误）。

之所以 returns 'nothing' 如果删除正则表达式是因为它仅在 spaces 上拆分 – 其中有在原始字符串中是 none – 然后 returns 每个对个单词。单件不能成对。

我怎样才能为字节文件自定义实现词袋？

how can I do a custom implementation of Bag of words for byte file?

python-3.x

bytecode

countvectorizer